Answer:
Step-by-step explanation:
Assuming that:
the promotion will be considered to be a success if more than 10% use the coupons received.
and coupons are sent to 100 credit card customers.
Then, the null hypothesis and alternative hypothesis is:
sample size n = 100
Using the eagle file data;
the no of people in the sample who use the coupon = 13
then,
Test statistics can be computed as:
At ∝ = 0.05
Since, P-value is greater than ∝, then we fail to reject 
.
Therefore, Eagle should not go with the promotion; a larger sample should be taken.
Answer:
<u>The company should promote a lifetime of </u><u>3589 hours</u><u> for these bulbs, so that only 2% of them burnout before the claimed lifetime.</u>
Step-by-step explanation:
Consider the lifetime of light bulbs is normally distributed. Then, μ = 4000 hours and σ = 200 hours.
Let X be the lifetime of bulbs. We need to find the lifetime before which only 2% (0.02) of the bulbs burn out. Suppose the value of this lifetime is y. then, we need to find out P(X<y) = 0.02.
We will use the z-score formula:
<u>z = (x-μ)/σ</u>
P(X<y) = 0.02
P((X-μ)/σ < (y-μ)/σ) = 0.02
P(z < (y-4000)/200) = 0.02
We can find the value of z at which the probability is 0.02 from the normal distribution (areas under the normal curve) table.
From the table we can see that 0.02 lies between z values -2.05 and -2.06. So,
z = [-2.05 + (-2.06)]/2
= -4.11/2
z = -2.055
So,
(y-4000)/200 = -2.055
y-4000 = -411
y = 4000 - 411
y = 3589 hours
<u></u>
<u>The company should promote a lifetime of </u><u>3589 hours</u><u> for these bulbs, so that only 2% of them burnout before the claimed lifetime.</u>
Answer:
D
Step-by-step explanation:
it reflects
Required root is p(x) = (x - (1 + i))(x - (1 - i)) = (x - 1 - i)(x - 1 + i) = x^2 - x + ix - x + 1 - i - ix + i + 1 = x^2 - 2x + 2
P(x) = x^2 - 2x + 2
Answer:
(3 laps / minute) (9 minutes) = 27 laps
Step-by-step explanation:
