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Lady_Fox [76]
2 years ago
10

Find the midpoint M of the line segment joining the points C = (-1, 1) and D = (5, – 7). = =

Mathematics
1 answer:
lukranit [14]2 years ago
5 0

Answer: (2,-3)

Step-by-step explanation:

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Dana needs 300 pickets for her colorful picket fence. She wants equal amounts of each of her 4 selected colors. She already has
Pavlova-9 [17]

Dana would need 75 pickets of each color to have an equal amount.

75x4=300

She would need 43 more red pickets to equal 75. (32+43=75)

49 more green pickets to equal 75 (26+49=75)

66 more yellow pickets to equal 75 (9+66=75)

75 blue pickets to equal 75. (0+75=75)

7 0
3 years ago
Read 2 more answers
I need help with this problem bk I’m so konfused by it
soldi70 [24.7K]

Do you want 5 and 6 or just 5? 5 is kind of neat.

44.5% = 0.445

4/9 = 0.4444444

You have enough information to put the numbers in order.

0.44 is the smallest number.

0.44444444.... is the next smallest number

0.4445 is bigger than the number above. 5 is in the ten thousandths place. that is bigger than 4 in the thousands place of 4/9

Finally the largest number of all is 0.445 for the same reason given above.

Six

5/12 = 0.416666

0.4

42% = 42/100 = 0.42

0.416

0.4 is the smallest number

0.416 is the next smallest number

0.41666666 is bigger than 0.416 because you are adding a bunch of 6s onto the decimal place.

The largest one is 0.42. You can put these into your calculator to verify the results. For example, 0.42 - 0.4166666 = 0.003344. Any result more than 0 will show that the first number is bigger than the second.

5 0
3 years ago
Better Products, Inc., manufactures three products on two machines. In a typical week, 40 hours are available on each machine. T
Kaylis [27]

Answer:

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

Step-by-step explanation:

                                Profit $    mach. 1      mach. 2

Product 1     ( x₁ )       30             0.5              1

Product 2    ( x₂ )       50             2                  1

Product 3    ( x₃ )       20             0.75             0.5

Machinne 1 require  2 operators

Machine   2 require  1  operator

Amaximum of  100 hours of labor available

Then Objective Function:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Constraints:

1.-Machine 1 hours available  40

In machine 1    L-H  we will need

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

2.-Machine 2   hours available  40

1*x₁  +  1*x₂   + 0.5*x₃   ≤  40

3.-Labor-hours available   100

Machine 1     2*( 0.5*x₁ +  2*x₂  +  0.75*x₃ )

Machine  2       x₁   +   x₂   +  0.5*x₃  

Total labor-hours   :  

2*x₁  +  5*x₂  +  2*x₃  ≤  100

4.- Production requirement:

x₁  ≤  0.5 *( x₁ +  x₂  +  x₃ )     or   0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

5.-Production requirement:

x₃  ≥  0,2 * ( x₁  +  x₂   +  x₃ )  or    -0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

General constraints:

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

The model is:

z  =  30*x₁  +  50*x₂  +  20*x₃      to maximize

Subject to:

0.5*x₁  +  2*x₂  + 0.75*x₃  ≤  40

1*x₁  +  1*x₂   + 0.5*x₃       ≤  40

2*x₁  +  5*x₂  +  2*x₃        ≤  100

0.5*x₁  -  0.5*x₂  -  0.5*x₃  ≤ 0

-0.2*x₁  - 0.2*x₂ + 0.8*x₃   ≥  0

x₁  ≥   0       x₂    ≥   0       x₃     ≥   0           all integers

After 6 iterations with the help of the on-line solver AtomZmaths we find

z (max)  =  1250 $

x₁  = 25    x₂  =  0   x₃  =  25

6 0
3 years ago
The perimeter of a rhombus is 560 meters and one of its diagonals has a length of 76 meters. Find the area of the rhombus.
borishaifa [10]
The perimeter is the sum of the side lengths of a shape. <span> A </span>diagonal is a line segment joining two vertices of a polygon or polyhedron <span>when those vertices are not on the same edge. We calculate as follows:

Perimeter = 4a
560 = 4a
a = 140 meters

</span>A=(1/2)d√(4a^2 - d^2)
A = 10240.56 m^2
4 0
3 years ago
The length of a flag is 0.3 foot less than twice its width. if the perimeter is 14.4 feet longer than the width, find the dimens
dem82 [27]
3.0 by 3.6  would be the dimensions
3 0
3 years ago
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