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3 years ago

How do I find the answer

Mathematics

2 answers:

Sophie [7]3 years ago

7 0

Answer:

Look for it

Step-by-step explanation:

Hitman42 [59]3 years ago

6 0

Answer:

to what

Step-by-step explanation:

?????

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Corey went shopping and bought a pair of shoes for $65.99 and two caps for $15.99 each. If he was charged a sales tax of 8%, the

RUDIKE [14]

Answer:

It’s 105

Step-by-step explanation:

6 0

3 years ago

A random sample of 16 statistics examinations was taken. The average sample score was 76.2 with a sample variance of 144. The 99

dlinn [17]

99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

<h3>What is the margin of error in statistics?</h3>

The margin of error is a statistic that describes how much random sampling error there is in survey results. One should have less faith that a poll's findings would accurately reflect those of a population census the higher the margin of error.

The interval will be calculated as below:-

Confidence interval = mean +/- margin of error (E)

mean = 76.2

variance = 144

sd = sqrt(variance) = sqrt(144) = 12

n = 16

Degree of freedom (df) = n - 1 = 16- 1 = 15

Confidence level (C) = 99% = 0.99

Significance level = 1 - C = 1 - 0.99 = 0.01 = 1%

t-value corresponding to 15 df and 1% significance level is 2.95

The margin of error will be:-

E = t×sd/√n = 2.95 × 12/√16 = 8.85

The interval will be:-

Lower limit = mean - E = 76.2 - 8.85 = 67.35

Upper limit = mean + E = 76.2 + 8.85 = 85.05

Therefore, the 99% confidence interval for the population average examination score is between a lower limit of 67.35 and an upper limit of 85.05. The correct option is C.

To know more about margin of error follow

brainly.com/question/24289590

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4 0

2 years ago

Alice is paying her bill at a restaurant. The tax on the cost of her meal is 5%. She decides to leave a tip of 20% of the cost o

AnnyKZ [126]

5% is 0.05 in decimals. To get 5% of M, multiply it. To convert a percentage into decimals, divide the number by 100. 20/100 is 0.2. 0.2 is the tip. Do the same as 0.05 and add in the actual cost of the meal (M). Check image

6 0

3 years ago

A researcher wishes to estimate the number of households with two cars. How large a sample is needed in order to be 99% confiden

solmaris [256]

Answer:

Sample size n = 1382

so correct option is D) 1382

Step-by-step explanation:

given data

confidence level = 99 %

margin of error = 3%

probability = 25 %

to find out

How large a sample size needed

solution

we know here P = 25 %

so 1 - P = 1 - 0.25

1 - P = 0.75

and we know E margin of error is 0.03 so value of Z for 99%

α = 1 - 99% = 1 - 0.99

α = 0.01

and $\frac{\alpha}{2}$ = $\frac{0.01}{2}$

$\frac{\alpha}{2}$ = 0.005

so Z is here

$Z_(\frac{\alpha}{2})$ = 2.576

sample size will be

Sample size n = $(\frac{(Z_(\frac{\alpha}{2})}{E})^2 * P * (1-P)$

put here value

Sample size n = (\frac{2.576}{0.03})^2 * 0.25 * 0.75

Sample size n = 1382

so correct option is D) 1382

3 0

4 years ago

325 people were in a tour group.Six buses were completely filled and 7 people choose to walk.How many people did the bus hold

Zolol [24]

(325 - 7)÷ 6= 53
.....

4 0

3 years ago

How do I find the answer​

How do I find the answer