Both the numerator and the denominator are divisible by 2.
(4/2)/(10/2) so the simplest form would then be 2/5
Your answer is: 2/5
Answer:
x = 29/6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
8x - (2x - 13) = 42
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Distributive Property] Distribute negative: 8x - 2x + 13 = 42
- [Subtraction] Combine like terms: 6x + 13 = 42
- [Subtraction Property of Equality] Subtract 13 on both sides: 6x = 29
- [Division Property of Equality] Divide 6 on both sides: x = 29/6
<u>Step 3: Check</u>
<em>Plug in x into the original equation to verify it's a solution.</em>
- Substitute in <em>x</em>: 8(29/6) - [2(29/6) - 13] = 42
- Multiply: 116/3 - [29/3 - 13] = 42
- [Brackets] Subtract: 116/3 - -10/3 = 42
- Subtract: 42 = 42
Here we see 42 does indeed equal 42.
∴ x = 29/6 is the solution.
The area of the square is calculated through the equation,
Area = e²
where e is the measure of sides.
From the given,
64 = e²
e = sqrt 64 = 8 inches
The length of the side of the square rotated to form the cylinder is the diameter of the base of the cylinder. To get the radius, we divide the diameter by 2.
radius = 8 inches / 2 = 4 inches
Thus, the radius of the cylinder is equal to <em>4 inches</em>.
Answer:
9n+18(2n-6)+13
Step-by-step explanation:
First, use distributive property to eliminate the parenthesis:
9n + 18(2n -6) + 13
9n + 36n - 108 + 13
Next, combine like terms:
9n + 36n - 108 + 13
45n - 108 + 13
45n + 121
Hope this helps!!
Alan~
Answer:
Step-by-step explanation:
we know that
The formula to calculate the depreciated value is equal to
where
V is the depreciated value
P is the original value
r is the rate of depreciation in decimal
x is Number of Time Periods
in this problem we have
substitute the values
