1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
svet-max [94.6K]
3 years ago
7

100 POINTS AND BRAINLIYEST!!!

Mathematics
1 answer:
Debora [2.8K]3 years ago
8 0

Answer:

<em>Preston is found correct as his sequence is a clear prove that trapezoid PQRS is similar to trapezoid KLMN, as shown in </em><em>attached figure a</em><em>.</em>

Step-by-step explanation:

<em>First please check the </em><em>attached figure a</em><em>, as you missed to add the figure. Hence, after a little research I was able to find the figure and I took that figure as a reference to answer your query, which anyways will clear your concept.</em>

<em>Tracking Chanel's Sequence:</em>

<em>Part (A) : Impact of rotating 90° counterclockwise about the origin</em>  

This is a fact that any point let say (x, y) is rotated 90° counterclockwise about the origin by transforming the point to (-y, x).  

So, the trapezoid PQRS with coordinates P(6,-4), Q(2,-2), R(2,-6) and S(6,-6) after rotating 90° counterclockwise about the origin would be transformed or changed to P'(4,6), Q'(2,2), R'(6,2), and S'(6,6). 

<em>Part (B) : Completing the table to determine the rule of rotating 90° counterclockwise about the origin  and filling the coordinate table</em>

As the rule suggests that any point let say (x, y) is rotated 90° counterclockwise about the origin by transforming the point to (-y, x), meaning, the positions of (x, y) are switched and the sign of original y-coordinate i.e is changed to its opposite.

So, the coordinates PQRS and P'Q'R'S' behave like this after rotating 90° counterclockwise about the origin.

<em>Original Coordinates </em>                 <em>New Coordinates</em>

(x, y)                     ⇒                       (-y , x)

P(6,-4)                  ⇒                       P'(4, 6)

Q(2,-2)                 ⇒                       Q'(2, 2)

R(2, -6)                 ⇒                       R'(6, 2)

S(6, -6)                 ⇒                       S'(6, 6)

<em>Part (C) : Impact of dilation on the coordinates of a shape by a scale factor of 1/2</em><em> </em>

It is an established fact that the coordinates are reduced by a factor of 1/2 if there is a dilation be a scale factor of 1/2.

<em>Part (D) : Completing the table to determine the rule of of dilation on the coordinates of a shape by a scale factor of 1/2 and filling the coordinates </em>

As the rule suggests that if any point let say (x, y) is dilated by a scale factor of 1/2, it would transform the point to P(1/2x, 1/2y).

Hence, following would be the coordinates after dilation by a scale factor of 1/2.

<em>Original Coordinates </em>                 <em>New Coordinates</em>

(x, y)                       ⇒                       (1/2x , 1/2y)

P'(4, 6)                   ⇒                        P"(2, 3)

Q'(2, 2)                  ⇒                        Q"(1, 1)

R'(6, 2)                   ⇒                        R"(3, 1)

S'(6, 6)                   ⇒                        S"(3, 3)

<em>Tracking Preston's Sequence:</em>

<em>Part (E) : Impact of reflection across x-axis  on the coordinates of shape</em>

This is a fact that when any point let say (x, y) is reflected across x-axis, it transforms or changes the point to (x, -y).

So, the trapezoid PQRS with coordinates P(6,-4), Q(2,-2), R(2,-6) and S(6,-6) after reflection across x-axis would be transformed or changed to P'(6, 4), Q'(2, 2), R'(2, 6), and S'(6,6).

<em>Part (F) : Completing the table to determine the rule of reflection across x-axis  and filling the coordinate table</em>

As the rule suggests that This is a fact that when any point let say (x, y) is reflected across x-axis, it transforms or changes the point to (x, -y), meaning, the the x coordinate of (x, y) remains the same but the sign of original y-coordinate i.e is changed to its opposite.

So, the coordinates PQRS and P'Q'R'S' behave like this after reflection across x-axis.

<em>Original Coordinates </em>                 <em>New Coordinates</em>

(x, y)                     ⇒                       (x , -y)

P(6,-4)                  ⇒                       P'(6, 4)

Q(2,-2)                 ⇒                       Q'(2, 2)

R(2, -6)                 ⇒                       R'(2, 6)

S(6, -6)                  ⇒                       S'(6, 6)

<em>Part (G) : Impact of dilation on the coordinates of a shape by a scale factor of 1/2</em><em> </em>

It is an established fact that the coordinates are reduced by a factor of 1/2 if there is a dilation be a scale factor of 1/2.

<em>Part (H) : Completing the table to determine the rule of of dilation on the coordinates of a shape by a scale factor of 1/2 and filling the coordinates </em>

As the rule suggests that if any point let say (x, y) is dilated by a scale factor of 1/2, it would transform the point to P(1/2x, 1/2y).

Hence, following would be the coordinates after dilation by a scale factor of 1/2.

<em>Original Coordinates </em>                 <em>New Coordinates</em>

(x, y)                      ⇒                       (1/2x , 1/2y)  

P'(6, 4)                   ⇒                       P''(3, 2)

Q'(2, 2)                  ⇒                        Q''(1, 1)

R'(2, 6)                   ⇒                        R''(1, 3)

S'(6, 6)                   ⇒                        S''(3, 3)

<em>Part (I) Comparing the Chanel's Sequence and Preston's Sequence answers with the final figure with the following coordinates:</em>

<em>K(3, 2)</em>

<em>L(1, 1)</em>

<em>M(1, 3)</em>

<em>N(3, 3)</em>

<em>If we check the </em><em>attached figure a</em><em> and compare the results of Chanel's Sequence and Preston's Sequence with the </em><em>attached figure a</em><em>. It is clear that Preston's sequence was right.</em>

<em> </em><em>Hence, Preston is found correct as his sequence is a clear prove that trapezoid PQRS is similar to trapezoid KLMN, as shown in </em><em>attached figure a. </em><em>This was the result of sequence of reflection across x-axis  and dilation on the coordinates of a shape by a scale factor of 1/2. And this sequence was suggested by Preston.</em>

<em>Keywords:  reflection, rotation, dilation, trapezoid</em>

<em>Learn more</em><em> about translation, reflection, dilation and trapezoid from brainly.com/question/7287774</em>

<em>#LearnwithBrainly</em>

You might be interested in
A car is traveling at a rate of 81 kilometers per hour. What is the car's rate in kilometers per minute? How many kilometers wil
shusha [124]
Only doing thos for the getting to knothinf
8 0
4 years ago
Do u just plot the numbers on the graph like (1,26)???
kvv77 [185]

Answer:

Yes

Step-by-step explanation:

Make sure you plot each number on the right axis. :)

4 0
3 years ago
The nearest perfect square that is less than 22 is
Andrew [12]

Answer:

16

Step-by-step explanation:

The square numbers are

1² = 1

2² = 4

3² = 9

4² = 16 ← this is the closest perfect square

5² = 25 (not applicable, over 22)

5 0
3 years ago
The number of eggs e in the carton and the total costs t of the eggs. what is the dependent variable
just olya [345]
T because you need to know the number of eggs, e, to know how much it costs.
6 0
3 years ago
2/3x+5=1 what is the solution to the equation shown?
Fudgin [204]

Answer:

x = - 6

Step-by-step explanation:

Given

\frac{2}{3} x + 5 = 1 ( subtract 5 from both sides )

\frac{2}{3} x = - 4

Multiply both sides by 3 to clear the fraction

2x = - 12 ( divide both sides by 2 )

x = - 6

7 0
4 years ago
Read 2 more answers
Other questions:
  • Yolanda wanted to buy a total of 6 pounds
    6·1 answer
  • imagine you live only one mile from work and you decide to walk.if you walk four milesb per hour how long will it take you to wa
    13·1 answer
  • Determine if the statement is true or false. Any linear system with more variables than equations cannot have a unique solution.
    13·1 answer
  • Help me do the ones marked with red.
    13·1 answer
  • Someone please help me ASAP <br> serious answers only <br><br><br> Options D is 5/2
    13·2 answers
  • How many angles must be supplementary with angle 14? 4 lines intersect to form 16 angles. The angles created, clockwise from top
    9·2 answers
  • Solve<br> y=-x2+2x+10<br> y=x+4
    8·1 answer
  • Yeah I have zero idea what this is, can someone help me with it?
    5·1 answer
  • Find the measure of the unknown angle.
    13·1 answer
  • There are 88 girls and 96 boys in the sixth-grade what is the rate of girls to boys
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!