The question states that both parts of Noshi's desk were shaped like trapezoids and both had a height of 3.
We know that the formula for area of a trapezoid is (a+b)/2 * h, where a and b are bases of the trapezoid and h is the height. Note: This is like any other form of trying to find the area, because we are doing base times height, however, we need to divide the sum of the bases by 2 to find the average base length.
Let's call the first trapezoid on the left Trapezoid A and the second slanted trapezoid Trapezoid B.
Area of Trapezoid A = (a+b)/2 * h = (5+8)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
Area of Trapezoid B = (a+b)/2 * h = (4+9)/2 * 3 = 13/2 * 3 = 6.5 * 3 = 19.5 feet
To find the area of Noshi's total desk, we simply need to add the areas of Trapezoid A and Trapezoid B together.
19.5 feet + 19.5 feet = 39 feet
Therefore, the area of Noshi's desk is 39 feet.
Hope this helps! :)
Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper =
sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining = 
= 
Using algebraic formula: 

Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
Answer:
382 cm²
Step-by-step explanation:
Front face + Back face:
A = 2(a + b)h/2
A = 2(14 cm + 8 cm)(7 cm)/2
A = 154 cm²
Left face:
A = 7 cm × 6 cm = 42 cm²
Right face:
A = 9 cm × 6 cm = 54 cm²
Bottom face:
A = 14 cm × 6 cm = 84 cm²
Top face:
A = 6 cm × 8 cm = 48 cm²
Total surface area =
= (154 + 42 + 54 + 84 + 40) cm²
= 382 cm²
Answer:
that will be 25 if you put 30 in the thing
42/60, x/320. 320/60=5.33333, 42*5.33333=224. So, about 224 students would ride the bus.