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vichka [17]
3 years ago
10

naomi has earned $54 mowing lawns the past two days. she worked 2.5 hours yesterday and 4.25 hours today. if namoni is paid the

same amount for every hour she works,how much does she earn per hour to mow lawns?
Mathematics
1 answer:
SSSSS [86.1K]3 years ago
7 0
First I added 2.5+4.25=6.75
Then do $54/6.75=$8
Answer=$8
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F(x) = x2 + 1<br> What is f(f(x))?<br> O x + 2x²+1<br> O x + 2x²+2<br> x + 2<br> x+1
nadya68 [22]

Answer:

It's x^4+2x^2+2

Step-by-step explanation:

The argument of f(f(x)) function becomes x^2+1-> F=(x^2+1)^2+1 Opening the brackets you get my answer. Not sure if O sign stood for ^4.

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amid [387]
The answer could be x = -y
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Help me to solve this
BartSMP [9]

Step-by-step explanation:

first we use Pythagoras to get t :

c² = a² + b²

with c being the Hypotenuse.

so,

t² = r² + s² = 10² + 31² = 100 + 961 = 1061

t = sqrt(1061)

and then we use the law of sine :

a/sin(A) = b/sin(B) = c/sin(C)

with the angles being opposite of their related sides.

so, r/sin(R) = t/sin(T) = t/sin(90) = t/1 = t

sin(R) = r/t = 10/sqrt(1061) = 0.30700278...

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Solving with percent and percent problems
Marysya12 [62]
Well, if 0.4% was defected, then 99.6% of the parts are good, because 100-0.4 is 99.6. Multiply 99.6% with 54650, and you get 54431.4. You should round down, because you can't have parts of parts. So, 54431 parts were good.  
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3 years ago
I will mark brainliest for the 1st and second answer but I need this before midnight
lozanna [386]

Answer:

4.

A = arcsin(BC/AB)  = arcsin(4/10)  = ~23.58 deg

B = arccos(BC/AB) = arccos(4/10)= ~66.42 deg

AC = sqrt(AB^2-BC^2) = sqrt(10^2-4^2) = 9.16

5.

A = 90-B=90-20 =70

AB = AC/sinC = 30/sin(20deg) = ~87.71

BC = sqrt(AB^2-AC^2) = sqrt(87.71^2-30^2) = ~82.42

6.

AB = AC/cosA =125/cos(50deg) = ~194.46

B = 90-A = 90-50 =40

BC = sqrt(AB^2-AC^2) = sqrt(194.46^2-125^2) = ~148.96

7.

AB = AC/cosA =8/cos(20deg) = ~8.51

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BC = sqrt(AB^2-AC^2) = sqrt(8.51^2-8^2) =~2.90

4 0
3 years ago
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