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3 years ago

How do I solve this substitution equation?

Mathematics

1 answer:

Tamiku [17]3 years ago

3 0

You solve this by using google.com or YouTube.com

Or just pay attention in class to get this.

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A kite is flying 20 ft off the ground. Its line is pulled taut and casts a 15 ft - shadow. Find the length of the line. If neces

Kryger [21]

Answer:

The answer to your question is 25 ft

Step-by-step explanation:

Data

height = 20 ft

leg = 15 ft

length of the line = ?

To solve this problem use the Pythagorean theorem.

Height = short leg = b

leg = long leg = a

length of the line = hypotenuse = c

- Substitution

c² = (20)² + (15)²

-Simplification

c² = 400 + 225

c² = 625

-Result

c = $\sqrt{625}$

c = 25 ft

6 0

3 years ago

Diego made 6 boxes of spaghetti to feed the 20 people who attended his dinner party.

sdas [7]

15
3 box per 10 people
3x5=15

3 0

2 years ago

Read 2 more answers

The area of a rectangle is represented by the function A = n^3 - 6n^2 - 8n + 48.

aliya0001 [1]

Answer:

P = 2(n - 6) + 2(n^2 - 8)

Step-by-step explanation:

Remembering that Area = Length times Width, we factor the given function

A = n^3 - 6n^2 - 8n + 48 in the expectation that the resulting factors represent the length and width respectively:

A = n^3 - 6n^2 - 8n + 48 factors as follows:

A = n^2(n - 6) - 8(n - 6), or A = (n - 6)(n^2 - 8)

We can label '(n - 6)' "width" and '(n^2 - 8'

length.

Then the perimeter, P, of the rectangle is P = 2(length) + 2(width). which works out here to:

P = 2(n - 6) + 2(n^2 - 8)

5 0

3 years ago

Is a banana 14 cm or 30 cm

bagirrra123 [75]

I have never see a banana 30cm, so 14cm is the right answer.

3 0

3 years ago

Read 2 more answers

What is the area of a rectangle with vertices at (4, 3), (11, 3), (11, 9), and (4, 9)?

Brums [2.3K]

Answer:

The area of a rectangle is 42 units ².

Step-by-step explanation:

As the diagram is given below.

Distance Formula

$Distance\ formula = \sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

As the rectangle with vertices at A (4, 3), B(11, 3),C (11, 9), and D (4, 9).

Take A (4, 3) to B(11, 3)

$AB = \sqrt{(11-4)^{2}+(3-3)^{2}}$

$AB = \sqrt{(7)^{2}+(0)^{2}}$

$AB = \sqrt{49}$

$\sqrt{49} =7$

AB = 7 units

As take B(11, 3) to C (11, 9).

$BC = \sqrt{(11-11)^{2}+(9-3)^{2}}$

$BC = \sqrt{(0)^{2}+(6)^{2}}$

$BC = \sqrt{36}$

$\sqrt{36} =6$

BC = 6 units

As take C (11, 9) toD (4, 9).

$CD = \sqrt{(4-11)^{2}+(9- 9)^{2}}$

$CD = \sqrt{(7)^{2}+(0)^{2}}$

$CD = \sqrt{49}$

$\sqrt{49} =7$

CD = 7 units

As take D (4, 9) to A (4, 3)

$DA = \sqrt{(4-4)^{2}+(3-9)^{2}}$

$DA = \sqrt{(0)^{2}+(-6)^{2}}$

$DA = \sqrt{36}$

$\sqrt{36} =6$

DA = 6 units

Thus

AB = DC= 7 units

AD = BC = 6 units

Formula

Area of rectangle = Length × Breadth

Length = 7 units

Breadth = 6 units

Put value in the above

Area of rectangle = 7 × 6

= 42 units ²

Therefore the area of a rectangle is 42 units ².

6 0

3 years ago

Read 2 more answers