Not sure if the equation is
![\log_9x+\log_3(x^2)=\dfrac52](https://tex.z-dn.net/?f=%5Clog_9x%2B%5Clog_3%28x%5E2%29%3D%5Cdfrac52)
or
![\log_x9+\log_{x^2}3=\dfrac52](https://tex.z-dn.net/?f=%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%3D%5Cdfrac52)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot9^{\log_3(x^2)}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot9%5E%7B%5Clog_3%28x%5E2%29%7D)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot(3^2)^{\log_3(x^2)}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot%283%5E2%29%5E%7B%5Clog_3%28x%5E2%29%7D)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{2\log_3(x^2)}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot3%5E%7B2%5Clog_3%28x%5E2%29%7D)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^2)^2}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot3%5E%7B%5Clog_3%28x%5E2%29%5E2%7D)
![9^{\log_9x+\log_3(x^2)}=9^{\log_9x}\cdot3^{\log_3(x^4)}](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3D9%5E%7B%5Clog_9x%7D%5Ccdot3%5E%7B%5Clog_3%28x%5E4%29%7D)
![9^{\log_9x+\log_3(x^2)}=x\cdot x^4](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3Dx%5Ccdot%20x%5E4)
![9^{\log_9x+\log_3(x^2)}=x^5](https://tex.z-dn.net/?f=9%5E%7B%5Clog_9x%2B%5Clog_3%28x%5E2%29%7D%3Dx%5E5)
On the other side of the equation, we'd get
![9^{5/2}=(3^2)^{5/2}=3^{2\cdot(5/2)}=3^5](https://tex.z-dn.net/?f=9%5E%7B5%2F2%7D%3D%283%5E2%29%5E%7B5%2F2%7D%3D3%5E%7B2%5Ccdot%285%2F2%29%7D%3D3%5E5)
Then
![x^5=3^5\implies\boxed{x=3}](https://tex.z-dn.net/?f=x%5E5%3D3%5E5%5Cimplies%5Cboxed%7Bx%3D3%7D)
- If it's the second one instead, you can use the same strategy as above:
![x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot x^{\log_{x^2}3}](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3Dx%5E%7B%5Clog_x9%7D%5Ccdot%20x%5E%7B%5Clog_%7Bx%5E2%7D3%7D)
![x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot\left((x^2)^{1/2}\right)^{\log_{x^2}3}](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3Dx%5E%7B%5Clog_x9%7D%5Ccdot%5Cleft%28%28x%5E2%29%5E%7B1%2F2%7D%5Cright%29%5E%7B%5Clog_%7Bx%5E2%7D3%7D)
(Note that this step assume
)
![x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{(1/2)\log_{x^2}3}](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3Dx%5E%7B%5Clog_x9%7D%5Ccdot%28x%5E2%29%5E%7B%281%2F2%29%5Clog_%7Bx%5E2%7D3%7D)
![x^{\log_x9+\log_{x^2}3}=x^{\log_x9}\cdot(x^2)^{\log_{x^2}\sqrt3}](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3Dx%5E%7B%5Clog_x9%7D%5Ccdot%28x%5E2%29%5E%7B%5Clog_%7Bx%5E2%7D%5Csqrt3%7D)
![x^{\log_x9+\log_{x^2}3}=9\sqrt3](https://tex.z-dn.net/?f=x%5E%7B%5Clog_x9%2B%5Clog_%7Bx%5E2%7D3%7D%3D9%5Csqrt3)
Then we get
![9\sqrt3=x^{5/2}\implies x=(9\sqrt3)^{2/5}\implies\boxed{x=3}](https://tex.z-dn.net/?f=9%5Csqrt3%3Dx%5E%7B5%2F2%7D%5Cimplies%20x%3D%289%5Csqrt3%29%5E%7B2%2F5%7D%5Cimplies%5Cboxed%7Bx%3D3%7D)
Answer:
??? Ok so whats the question??
Step-by-step explanation:
How is 20/100 = 13...
Anyways, look at the two fractions.
20/100 and 80/100
Notice how 20 times 4 equals 80?
So maybe, 13 * 4 = 52.
2 Red — 7 Green — 4 Blue — 11 Random
2 + 7 + 4 + 11 = 24
Probability of Green falling.
7/24
Hope this helps
Answer:
can i see the numbers
Step-by-step explanation:
there is no picture