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coldgirl [10]
1 year ago
6

There are 16 people in a running race. The first 3 people to finish the race will he given prizes. How many different ways can t

he first, second, and third place prizes be awarded?
Mathematics
1 answer:
rodikova [14]1 year ago
7 0

Answer : 3, 360 ways

Total number of people running the race = 16

We have three slot to be filled for first, second and third

Any person can take the first position irrespective of the arrangement

one out of the 16 people can come first

out of the 15 people remaining , one person can also come second remaining 14

out of the 14 people, one person can also come third

The number of ways the gift can be awarded = 16 x 15 x 14

The nummber of ways the prizes can be awarded = 3360 ways

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The local parts shop buys a machine that costs $500000. Its value depreciates exponentially each year by 10%. What is the machin
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. Fiona has $1.20 with which to buy some ribbon.The ribbon is on sale for $0.08 per foot.How many feet of ribbon can Fiona buy
gogolik [260]

Respuesta: 4.5 pies que puede comprar si tiene $ 11.25

Explicación paso a paso:

Dado que hemos dado que

Costo de los dulces por pie = $ 2.50

Dinero total que gastó en dulces = $ 11.25

Sea x el número de pies que puede comprar

Ahora, según la pregunta, obtenemos eso,

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8 0
3 years ago
what fraction is equivalent to -3/2? i’m going to keep writing because it has to be 20 words. Anyways thank you if you answer th
Alinara [238K]
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2 years ago
Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity. In the given triangle ABC, angle A
lana66690 [7]

The relationship between the lengths of the sides of a right triangle are

given by Pythagoras theorem.

  • Part A: <u>ΔABC is similar to ΔADC</u>
  • Part B: ΔABC and ΔADC are similar according <u>AA similarity postulate</u>
  • Part C: <u>DA = 6</u>

Reasons:

Part A:

∠A = 90°

Segment AD ⊥ Segment BC

Location of point D = Side BC

Part A: In triangle ΔABC, we have;

∠A = 90°, ∠B = 90° - ∠C

In triangle ΔADC, we have;

∠ADC = 90°, ∠DAC = 90° - ∠C

∴ <u>ΔABC is similar to ΔADC</u> by Angle-Angle, AA, Similarity Postulate

Part B: The triangles are similar according to <u>AA similarity postulate</u>,

because two angles in one triangle are equal to two angles in the other

triangle and therefore, by subtraction property of equality, the third angle

in both triangles are also equal.

Part C: The length of DB = 9

The length of DC = 4

Required: Length of segment DA

In triangle ΔABD, we have;

∠BDA = 90°= ∠ADC

∠DAC ≅ ∠B by Congruent Parts of Congruent Triangles are Congruent

Therefore;

ΔABD ~ ΔADC by AA similarity, which gives;

\displaystyle \frac{\overline{DA}}{\overline{DC}}  = \frac{\overline{BD}}{\overline{DA}}

\overline{DA}^2 = \overline{DC} \times \overline{BD}

Which gives;

\overline{DA}^2 = 4 × 9 = 36

\overline{DA} = √(36) = 6

\overline{DA}<u> = 6</u>

Learn more here:

brainly.com/question/2269451

3 0
2 years ago
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