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myrzilka [38]
4 years ago
15

3x-7y=13 What is y? Need awnser

Mathematics
2 answers:
olga nikolaevna [1]4 years ago
7 0

The answer is y = -13/7 + 3x/7

zepelin [54]4 years ago
4 0

Answer:

y= -13-3x÷7

Step-by-step explanation:

1st Subtract 3x from both sides: 3x-7y-3x=13-3x

2nd Simplify: -7y=13-3x

3rd Divide both sides by -7: -7y÷-7=13÷-7-3x÷-7

4th Simplify: -13-3x÷7

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Hope this helps you out :)

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Two water pumps are filling a pool. One of the pumps is high power and can fill the pool 5 hours before the other can do. Howeve
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L = hours for the slower pump to fill the pool

L - 5 = hours for the high power pump, since it can do it in 5 hours less.

since the slower pump takes L hours, the faster pump takes then L - 5 hours.

we know both pumps together take 3 hours to do <u>half of the pool</u>, so that means that to fill up <u>the whole pool it takes them 6 hours</u>.

since the slower pump can do it alone in L hours, in 1 hour it has done 1/L of the whole thing.

likewise, since the faster pump can do it in L-5 hours, in 1 hour alone it has done 1/(L-5) of the whole job.


\bf \stackrel{\textit{slower pump's rate}}{\cfrac{1}{L}}~~~~+\stackrel{\textit{faster pump's rate}}{\cfrac{1}{L-5}}~~~~=~~~~\stackrel{\textit{total done in 1 hour}}{\cfrac{1}{6}} \\\\\\ \textit{let's multiply both sides by }\stackrel{LCD}{6(L)(L-5)}\textit{ to do away with the denominators} \\\\\\ 6(L)(L-5)\left( \cfrac{1}{L}+\cfrac{1}{L-5} \right)=6(L)(L-5)\left( \cfrac{1}{6} \right)


\bf 6(L-5)+6L=(L)(L-5)\implies 6L-30+6L \\\\\\ 12L-30=L^2-5L\implies 0=L^2-17L+30 \\\\\\ 0=(L-15)(L-2)\implies L= \begin{cases} \boxed{15}\\ 2 \end{cases}


now, we can't use L = 2, because, the whole job by both is done in 6 hours, there's no way the slower pump can do it in less than that, so L = 15.

now if L = 15, then L - 5 = 10.

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