3 years ago

Can someone help me I need it.

1 answer:

6 0

Answer:

C is the answer 3rd one...

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vovikov84 [41]

$S$ is the disk of radius 1 parallel to the $x,y$ -plane and lying in the plane $z=16$ . Parameterize this surface by

$\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+16\,\vec k$

with $0\le u\le1$ and $0\le v\le2\pi$ . Take the normal vector to $S$ to be

$\vec r_u\times\vec r_v=u\,\vec k$

(the orientation doesn't matter because this is a scalar surface integral)

Then

$\displaystyle\iint_S(x-2y+z)\,\mathrm dS=\iint_S(u\cos v-2u\sin v+16)\|u\,\vec k\|\,\mathrm du\,\mathrm dv$

$=\displaystyle\int_0^{2\pi}\int_0^1(u^2(\cos v-2\sin v)+16u)\,\mathrm du\,\mathrm dv=\boxed{16\pi}$

5 0

3 years ago

balandron [24]

Alright, we're in the home stretch here :) All you need to remember is that i² = -1. Otherwise, it is the same as FOIL

(3-2i)(1+7i)

3-2i+21i-14i² ← Replace the i² with -1, then simplify like numbers

3+19i+14

17+19i or C

8 0

3 years ago

sineoko [7]

The answer would be 850.85

6 0

3 years ago

Fiesta28 [93]

Answer:

Step-by-step explanation:

basic math :/

8 0

3 years ago

Natali5045456 [20]

Answer:

Step-by-step explanation:

5 0

3 years ago