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Mamont248 [21]
4 years ago
5

If angle 1 and angle 2 form a linear pair and angle 1 is 18 degrees less than five times the measure of angle 2, then the angle

1 is _____ degrees
Mathematics
1 answer:
Juliette [100K]4 years ago
7 0

Answer:

Angle 1 is 147 degrees

Step-by-step explanation:

When two angles form a linear pair, then we have the intersection of two lines

So what this mean is that both angles lie on a straight line and the sum of both angles is 180.

Let the angle 2 be x

We are told that angle 1 is 18 degrees less than 5 times the measure of angle 2;

What we are saying here is that; angle 1 = 5x - 18

So let’s add both together to give 180

angle 1 + angle 2 = 180

x + 5x -18 = 180

6x = 180+ 18

6x = 198

x = 198/6

x = 33 degrees

But angle 1 is 5x -18 = 5(33) -18 = 165 -18 = 147 degrees

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Two cars traveled equal distances in different amounts of time. Car A traveled the distance in 4 h, and Car B traveled the dista
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40mph for Car B I think. 45mph for Car A. 45(mph) times 4(h) is 180(distance) and 40 times 4.5 is also 180. Sorry if I'm wrong.

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4 years ago
Please help me look at the attached picture
Lady bird [3.3K]

Answer:

Q(-10) = 299

Step-by-step explanation:

Q(x) = 3x^{2} - 1Q(-10) = 3(-10)^{2} - 1

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Q(-10) = 300 - 1  3 times 100 equal 300

Q(-10) = 299

5 0
4 years ago
A line plot titled Household T V Ownership has Number of televisions on the x-axis. There is x about 0, 2 above 1, 4 above 2, 7
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8 0
4 years ago
Segment CD has point E located on it such that CE:ED = 3:5. If the endpoints are located at C(5, -6) and D(11,18) then what are
wlad13 [49]

Answer:

E(29/4,3)

Step-by-step explanation:

Given that,

Segment CD has point E located on it such that CE:ED = 3:5

The coordinates of C and D are (5, -6) and (11,18) respectively.

We need to find the coordinates of E. Let the coordinates are (x,y). Using section formula to find it as follows :

(x,y)=(\dfrac{m_1x_2+m_2x_1}{m_1+m_2},\dfrac{m_1y_2+m_2y_1}{m_1+m_2})\\\\(x,y)=(\dfrac{3(11)+5(5)}{3+5},\dfrac{3(18)+5(-6)}{3+5})\\\\=\dfrac{29}{4},3

So, the coordinates of E are (29/4,3).

4 0
3 years ago
What is the area of the sector ?​
worty [1.4K]

They forget to say "not to scale".  I'm guessing this is trig because I don't see another way to do it.

Let's consider x=chord PQ first.  By the Law of Cosines

x^2 = 3^2 + 5^2 - 2(3)(5) \cos 81^\circ = 34 - 30\cos 81^\circ

We have an isosceles triangle formed by two radii of 9 cm and x=PQ.  By the Law of Cosines again,

x^2 = 9^2 + 9^2 - 2(9)(9) \cos B

x^2 = 162 - 162 \cos B

\cos B = \dfrac{162 - x^2}{162} = 1 - \dfrac{x^2}{162}

\cos B = 1 - \dfrac{34 - 30\cos 81^\circ}{162}

B = \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ }{162} \right)

The area of the circle is the fraction given by the angle,

A = \dfrac{B}{360^\circ} \pi r ^2

A \approx \dfrac{ \arccos \left(1 - \dfrac{34 - 30\cos 81^\circ}{162} \right) }{360} (3.142)9^2

A\approx 24.7474332960707

Answer: 24.7 sq cm

8 0
3 years ago
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