I didn't mean to post the answer and can't figure out how to take it down. Somebody report it so it does go down and the question can be later answered. Thank you
Answer:
0.049168726 light-years
Step-by-step explanation:
The apparent brightness of a star is
where
<em>L = luminosity of the star (related to the Sun)
</em>
<em>d = distance in ly (light-years)
</em>
The luminosity of Alpha Centauri A is 1.519 and its distance is 4.37 ly.
Hence the apparent brightness of Alpha Centauri A is
According to the inverse square law for light intensity
where
light intensity at distance
light intensity at distance
Let
be the distance we would have to place the 50-watt bulb, then replacing in the formula
Remark: It is worth noticing that Alpha Centauri A, though is the nearest star to the Sun, is not visible to the naked eye.
Answer:
they are equivalent
Step-by-step explanation:
because 4 times 9 is 36 and 4 times 5 is 20 so it is equal to 36+20
25.7 because that is the answer