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exis [7]
3 years ago
12

9. Write an equation for the line that is parallel to the given line and that passes through the given point.

Mathematics
1 answer:
timurjin [86]3 years ago
7 0

Answer:

  y -11 = 2(x -3)

Step-by-step explanation:

The slope of the given line is the x-coefficient: 2. The parallel line will have the same slope.

When you know the slope and a point on the line, it is convenient to use the point-slope form of the equation of a line:

  y -k = m(x -h) . . . . . . line with slope m through point (h, k)

Your line's equation is ...

  y -11 = 2(x -3)

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Find the equation of the tangent line to the curve 4x3+2y2−11=4xy−x at the point (−1,2).
katrin [286]
Hello : let : y = f(x)     so : y' = f'(x)
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by derivate : <span>4x3+2y2−11=4xy−x
12x² +4yy' = 4y +4xy' - 1
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if x = -1   y = 2 subsct in : (*)
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2y' = - 9 
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</span>of the tangent line to the curve <span>at the point (−1,2) is : 
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5 0
3 years ago
Select the correct answer. What is the solution to the equation?<br> *image below*
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Step-by-step explanation:

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Missing side of the triangle<br> 5 yds<br> 4yds
Vitek1552 [10]

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3 years ago
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