What is a chalculer.

You can be sentenced to up to 180 days in jail for driving with a license that was suspended for _________ .

Yanka [14]

Answer:c\

Explanation:

4 0

3 years ago

Professor Midas drives an automobile from Newark to Reno along Interstate 80. His carâ€™s gas tank, when full, holds enough gas

zmey [24]

Answer:

The GREEDY Algorithm

Explanation:

Based on the situation given in question, the Greedy algorithm shall give the optimal solution to professor

Suppose that the cities are at locations0 =x0< x1< . . . < x

We shall use the induction method to prove that G is the optimal solution valid for numbers less than n

We assume another solution Z which we initially consider to be optimum as well, based on that when Z fills the tank, it fills it to full level

Let us state the values in case of n intervals. Given below, we say that g1 is the first stop and z1 is also the first stop.

This can be written as ;

G=g1, g2, . . . , gk

Z=z1, z2, . . . , zk’

Here k’ <= k and k < n

Let I be an idex where for the first time gi is not equal to zi

Considering t= maxi Zi

Z′=g1, z2, z3, . . . , zk′

Now since z2, z3, . . . , zk′ should be an optimal stopping pattern for the problem otherwise we have chosen Z, with smaller gas filling (not feasible)

Using induction hypothesis we conclude thatg2, . . . , gk is an optimal stopping pattern, which is based on greedy algorithm

7 0

3 years ago

What is a spacecraft virus?

photoshop1234 [79]

A spacecraft virus is a type of bacteria virus that feeds on other bacteria. It got it name because it is mostly shaped like a spacecraft.

4 0

3 years ago

Read 2 more answers

The Hudson Engineering Group (HEG) has contacted you to create a conceptual model whose application will meet the expected datab

alexdok [17]

Answer:

The diagram of the ER and depreciation is in the attachments.

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3 years ago

Ask the user to input their grade percentage (e.g. the use will enter 98 if they had an overall grade of 98% in their course) fo

Airida [17]

Answer:

In Python

def getpointValue(subject):

if subject >= 75: point = 4; grade = 'A'

elif subject >= 60: point = 3; grade ='B'

elif point >= 50: point = 2; grade = 'C'

elif point >= 40: point = 1; grade = 'D'

else: point = 0; grade = 'F'

return point,grade

subjects= ["Accounting","Marketing","Economics","MIS"]

acct = int(input(subjects[0]+": "))

mkt = int(input(subjects[1]+": "))

eco = int(input(subjects[2]+": "))

mis = int(input(subjects[3]+": "))

acctgrade = getpointValue(acct)

print(subjects[0]+" Grade: "+str(acctgrade[1]))

mktgrade = getpointValue(mkt)

print(subjects[1]+" Grade: "+str(mktgrade[1]))

ecograde = getpointValue(eco)

print(subjects[2]+" Grade: "+str(ecograde[1]))

misgrade = getpointValue(mis)

print(subjects[3]+" Grade: "+str(misgrade[1]))

totalpoint = (acctgrade[0] + mktgrade[0] + ecograde[0] + misgrade[0]) * 3

gpa = totalpoint/12

print("GPA: "+str(gpa))

Explanation:

The solution I provided uses a function to return the letter grade and the point of each subject

I've added the explanation as an attachment where I used comment to explain difficult lines

Download txt

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3 years ago