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AURORKA [14]
3 years ago
12

At a fabrication plant, 9 of the employees each earn $10,000 per quarter and 1 employee earns $70,000 per quarter.

Mathematics
2 answers:
astraxan [27]3 years ago
8 0

A. 

$10,000

$10,000

$10,000

$10,000

<span>$10,000  </span>

$10,000

$10,000

$10,000

$10,000

$70,000

$160,000 / 10 = $16,000 Mean

Median = ($10,000 * 2 / 2) = $10,000

B.  He can advertise the position by emphasizing that a high initial compensation will be offered since $13,000 is greater than the previous salary offered to employees.

C. Yes, I agree because the previous salary offered was just $10,000 but now it is being increased to $13,000.

Aleonysh [2.5K]3 years ago
8 0
A
La media es 10,000
El promedio es 16,000
B
Mr Gomez podría poner en el anuncio que el promedio del sueldo de los trabajadores de su fábrica es 16,000, que es 3,000 más que lo que gana un trabajador promedio.

C

No estoy de acuerdo, por que en realidad el salario del 90% de los trabajadores de esa fábrica es 10,000, lo que está 3,000 por debajo de el salario promedio de otras fábricas.
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melomori [17]

Answer:

71°

Step-by-step explanation:

3x° + (x - 11)° + (2x - 55)° = 360°

3x + x - 11 + 2x - 55 = 360°

6x - 66 = 360°

6x = 360° + 66°

6x = 426°

x = 71°

8 0
3 years ago
What is the length of angle EF in the right triangle below
salantis [7]

Answer:

E.  √180

Step-by-step explanation:

Using Pythagoras' theorem

a^2 + b^2 = c^2 (c = hypotenuse, a and b are legs)

a^2 = c^2 - b^2

a^2 = 18^2 - 12^2

a^2 = 324 - 144

a^2 = 180

a = √180

Answer

E.  √180

6 0
3 years ago
Y is a random variable that is distributed N(-16, 1.21). Find k such that Prob(-15.043 &lt; Y ≤ k) = 0.1546. (Round your answer
IgorLugansk [536]

Transform <em>Y</em> to <em>Z</em>, which is distributed N(0, 1), using the formula

<em>Y</em> = <em>µ</em> + <em>σZ</em>

where <em>µ</em> = -16 and <em>σ</em> = 1.21.

Pr[-15.043 < <em>Y</em> ≤ <em>k</em>] = 0.1546

Pr[(-15.043 + 16)/1.21 < (<em>Y</em> + 16)/1.21 ≤ (<em>k</em> + 16)/1.21] = 0.1546

Pr[0.791 < <em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] - Pr[<em>Z</em> < 0.791] = 0.1546

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] = 0.1546 + Pr[<em>Z</em> < 0.791]

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.1546 + 0.786

Pr[<em>Z</em> ≤ (<em>k</em> + 16)/1.21] ≈ 0.940

Take the inverse CDF of both sides (<em>Φ(x)</em> denotes the CDF itself):

(<em>k</em> + 16)/1.21 ≈ <em>Φ⁻¹</em> (0.940) ≈ 1.556

Solve for <em>k</em> :

<em>k</em> + 16 = 1.21 • 1.556

<em>k</em> ≈ -14.118

8 0
3 years ago
If f(x)=4x^2+1 and g(x)=x^2-5 find(f+g)(x)
Zepler [3.9K]

Answer:

\large\boxed{(f+g)(x)=5x^2+6}

Step-by-step explanation:

(f+g)(x)=f(x)+g(x)\\\\f(x)=4x^2+1,\ g(x)=x^2-5\\\\\text{Substitute:}\\\\(f+g)(x)=(4x^2+1)+(x^2-5)\\\\=4x^2+1+x^2-5\qquad\text{combine like terms}\\\\=(4x^2+x^2)+(1+5)\\\\=5x^2+6

6 0
3 years ago
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