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amm1812
3 years ago
11

a total of 2 yards of fabric is used to make 5 identical pillows how much fabric is used for each pillow

Mathematics
2 answers:
Brut [27]3 years ago
8 0

²/₅ yards of fabric

<h3>Further explanation</h3>

<u>Given:</u>

A total of 2 yards of fabric is used to make 5 identical pillows.

<u>Question:</u>

How much fabric is used for each pillow?

<u>The Process:</u>

From the information above, we make a suitable diagram as follows:

\boxed{pillow}\boxed{pillow}\boxed{pillow}\boxed{pillow}\boxed{pillow} = 2 \ yards

The question is, how much fabric is used for each pillow.

\boxed{pillow} = ? \ yards

Let us calculate.

  • \boxed{ \ 5 \ pillow = 2 \ yards \ }
  • \boxed{ \ 1 \ pillow = ? \ yards \ }

\boxed{ \ = \frac{1}{5} \times 2 \ }

\boxed{ \ = \frac{2}{5} \ }

Thus the fabric is used as much as

\boxed{\boxed{ \ \frac{2}{5} \ yards \ }} to make each pillow.

In decimal,

\boxed{ \ \frac{2}{5} \times \frac{2}{2} = \frac{4}{10} = 0.4 \ }

- - - - - - - - - -

Quick Steps:

\boxed{ \ = 2 \ yards \div 5 \ pillow \ }

\boxed{ \ = \frac{2 \ yards}{5 \ pillow} \ }

\boxed{\boxed{ \ \frac{2}{5} \ yards \ to \ make \ each \ pillow \ }}

<h3>Learn more</h3>
  1. How many years did Sara live in Rochester? brainly.com/question/344729
  2. How many students are wearing a shirt other than blue or white? brainly.com/question/895261
  3. How much money Elise have after paying for the stamp? brainly.com/question/3207704

Keywords: a total of 2 yards of fabric, used, to make, 5 identical pillows, how much fabric, used for, each pillow

asambeis [7]3 years ago
4 0
0.4 hope this helped! :3 plz mark brainliest!
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3. Assume that the likelihood of a child under the age of ten watching PBS is 0.76. Three children are
natta225 [31]

Using the binomial distribution, the probabilities are given as follows:

a) 0.4159 = 41.59%.

b) 0.5610 = 56.10%.

c) 0.8549 = 85.49%.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

For this problem, the values of the parameters are:

n = 3, p = 0.76.

Item a:

The probability is P(X = 2), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.76)^{2}.(0.24)^{1} = 0.4159

Item b:

The probability is P(X < 3), hence:

P(X < 3) = 1 - P(X = 3)

In which:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 3) = C_{3,3}.(0.76)^{3}.(0.24)^{0} = 0.4390

Then:

P(X < 3) = 1 - P(X = 3) = 1 - 0.4390 = 0.5610 = 56.10%.

Item c:

The probability is:

P(X \geq 2) = P(X = 2) + P(X = 3) = 0.4159 + 0.4390 = 0.8549

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
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