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UNO [17]
3 years ago
15

Write 2x+y=5 in slope intercept form

Mathematics
2 answers:
Viefleur [7K]3 years ago
7 0


subtract 2x from each side so youre left with y =  5 -2x

rearrange the left side so it looks like -2x + 5

combine them y = -2x + 5

mylen [45]3 years ago
6 0
2x+y=5
To put this in slope intercept form, you simply have to get y by itself on the left side of the equation.
2x+y=5
2x+y-2x=5-2x
y=-2x+5
Now, I had to switch the right side around like that, because slope intercept form is y=mx+b
Because you're subtracting 2x from 5, it becomes 5 added to -2x when it's put in the correct form.
y=-2x+5
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Work shown please.. I need help with this topic.
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4 years ago
Find the solution of the system of equations. 3x+3y= 3x+3y= \,\,42 42 x-3y= x−3y= \,\,-22 −22
oee [108]

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Step-by-step explanation:

3 0
3 years ago
(SAT Prep) In the figure, if PN = LN, NP is parallel to MQ, and QL bisects ∠PQM, what is value of x?
rosijanka [135]

Answer:

x=67 degrees

Step-by-step explanation:

Same side interior angles are 180 degrees.

<PNL+54=180

<PNL=180-54

<PNL=126

Since |PN|=|NL|

2<PLN+126=180

2<PLN=180-126

2<PLN=54

<PLN=27

Angles on a straight line add up to 180

<PLN+<MLQ+70=180

27+<MLQ+70=180

<MLQ+97=180

<MLQ=180-97

<MLQ=83

<MQL+54+83=180----> sum of interior angles in triangle MQL is 180.

<MQL+137=180

<MQL=180-137

<MQL=43

But <MQL=43=<PQL ---> it was given that QL bisects ∠PQM

Now x+70+43=180----> sum of angles in triangle PQL

x=180-70-43

x=67\degree

7 0
3 years ago
Find the measure of angle x in the figure below:
BartSMP [9]
First, it's worth noting that angles on a straight line sum to 180°. We can use this information to find out the value of y:
180-52-59=69
y=69°
Another rule is that the angles in a triangle sum to 180° as well. This means that we can now find out x:
63+y+x=180
63+69+x=180
180-63-69=x
x=48°
3 0
3 years ago
Read 2 more answers
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