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777dan777 [17]
3 years ago
7

Fuel economy estimates for automobilos built in a certain yoar predicted a mean of 26.8 mpg and a standard deviation of 72 mpg f

or highway driving. Assume that a normal distribution can be applied. Within what
range are 99.8% of the automobiles?
Mathematics
1 answer:
kodGreya [7K]3 years ago
4 0

Answer:

range=u ± 3.09 sd

Step-by-step explanation:

Given:

mean, u= 26.8 mpg

standard deviation, sd=72 mpg

% contained in interval = 99.8%

the interval for 99.8% of the values of a normal distribution is given by

mean ± 3.09 standard deviation= u ± 3.09 sd

                                                      =26.8  ± 3.09(72)

                                                      =26.8 ± 222.48

                                                      = 249.28 , -195.68

range=u ± 3.09 sd = 249.28 , -195.68 !

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Answer:

(A) The population's growth rate in equation form is y = (0.016t * 7652) + 7652

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Step-by-step explanation:

(A) Y = the total population of the town. 0.016 is 1.6% just in its original form. T = the year in which were trying to find the town's total population. 7652 is the total population of the town in 2016. With this information, the equation reads, The total population of the town (Y) is equal to 16% (0.016) of the current year's population (T) added to 2016's population of 7652. (This last sentence can also be read what is 1.6% of the towns population in the year were trying to find. Because the population is always growing, 1.6% gets multiplied as to scale with the total population in year T)

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