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cluponka [151]
3 years ago
13

sapling, or young tree, is planted in a garden. After 3 years, it is 180 cm tall. After 7 years, it is 368 cm tall. How tall wil

l the tree be after 10 years?
Mathematics
1 answer:
vesna_86 [32]3 years ago
7 0
Sapling, or young tree, is planted in a garden. After 3 years, it is 180 cm tall. After 7 years, it is 368 cm tall. How tall will the tree be after 10years?<span> 
</span>
-509
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skelet666 [1.2K]
The answer would be 4832
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2x + 8 = 2(x + 4) help pls
Fynjy0 [20]
2x +8=2x+8
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HELP SOMEONE PLEASE!!!!! Factor completely 10x2 + 2x − 8. 2
natka813 [3]

Answer:

2(5x - 4)(x + 1)

Step-by-step explanation:

10x^2 + 2x − 8 =

First, factor out the GCF of all terms which is 2.

= 2(5x^2 + x - 4)

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= 2(5x      )(x       )

-4 factors into -4 and 1, -1 and 4, and -2 and 2. Use the set of two factors in the proper positions that will give the middle term.

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Quick algebra 1 question for 10 points!
Maslowich

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

<h3>What is the range of a quadratic equation?</h3>

In this case we have a <em>quadratic</em> equation whose domain is stated. The domain of a function is the set of x-values associated to only an element of the range of the function, that is, the set of y-values of the function. We proceed to evaluate the function at each element of the domain and check if the results are in the choices available.

x = - 9

y = (2 / 3) · (- 9)² - 6

y = 48

x = - 6

y = (2 / 3) · (- 6)² - 6

y = 18

x = - 3

y = (2 / 3) · (- 3)² - 6

y = 0

x = 0

y = (2 / 3) · 0² - 6

y = - 6

x = 3

y = (2 / 3) · 3² - 6

y = 0

x = 6

y = (2 / 3) · 6² - 6

y = 18

x = 9

y = (2 / 3) · 9² - 6

y = 48

The range of the <em>quadratic</em> function y = (2 / 3) · x² - 6 is {- 6, 0, 18, 48}.

To learn more on functions: brainly.com/question/12431044

#SPJ1

7 0
2 years ago
Says hint: divide, i dunno
lapo4ka [179]

distance= rate * time

distance/rate=time

(2.4 *10^20)/ (1.2*10^5)  = 2 * 10^15 seconds

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