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3 years ago

Write a quadratic equation in standard form such that -5 is it's only solution.

1 answer:

5 0

$\displaystyle\bf\\x_1=x_2=-5\\\\(x-x_1)(x-x_2)=0\\\\(x-(-5))(x-(-5))=0\\\\(x+5)(x+5)=0\\\\x^2+2\cdot x\cdot5 + 5^2=0\\\\\boxed{\bf x^2+10x + 25=0}$

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Which of the following represents the value of the missing side?

igomit [66]

Answer:

The value of the missing side is $x=2\ units$

Step-by-step explanation:

In this problem i assume that the length side x is tangent to the circle

the length side x is perpendicular to the radius

Applying the Pythagoras Theorem in the right triangle

we have that

$(1.5+1)^{2}=1.5^{2}+x^{2}$

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$x^{2}=2.5^{2}-1.5^{2}$

$x^{2}=4$

$x=2\ units$

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3 years ago

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Answer:

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3 years ago

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Which of the following is a secant on the circle below?

aliya0001 [1]

Answer:

A and B

Step-by-step explanation:

A secant is a line which intersects a circle at 2 points

SU and RT both intersect the circle at 2 points and are secants

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3 years ago

Points A and B have opposite x-coordinates but the same y-coordinates.

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Answer:what’s the question

Step-by-step explanation:

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2 years ago

Write a function G whose graph represents a vertical stretch by a factor of two followed by a translation one unit up of

expeople1 [14]

G(x)=2x+1 , vertical stretch by 2 units and shifted 1 unit up

Given :

Original function f(x)=x

To find :

Function G whose graph is a vertical stretch by 2 and move one unit up

We use the given function to for vertical stretch and shifting up

for Vertical stretch multiply the factor by f(x)

f(x) becomes 2f(x)

so the function becomes 2x

$f(x)=2f(x)=2x\\$

For moving up , we need to add the units at the end of the function

f(x)+1

2x+1

Hence, G(x)=2x+1

Learn more : /brainly.com/question/4521517

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3 years ago