<span>
(4w^2-3w+8) + (3w^2+9w+5) - (-8w^2+7w+3)
=</span><span>4w^2- 3w+ 8 + 3w^2+ 9w+ 5 + 8w^2 - 7w - 3
=15</span>w^2 - w + 10
hope it helps
Answer: y = 2/3x + 41/3
Step-by-step explanation:
First convert the equation into slope-intercept
3x + 6y = 4y - 4
-4y -4y
3x + 2y = -4
-3x -3x
2y = -3x - 4
y = -3/2x - 2
Perpendicular lines have a negative reciprocal for their slopes.
The negative reciprocal of -3/2 is 2/3
Now using the slope 2/3 you will use the formula y =mx +b and input the slope, and the x and y coordinates of the given point, (-10,7), to solve for the y-intercept.
7 = 2/3(-10) + b
7 = -20/ 3 + b
+ 20/3 + 20/3
b = 20/3 + 21/3 = 41/3
Since the the y-intercept is 41/3 then the equation will be , y = 2/3x + 41/3
The area is 448.5
(13 × 29) + (11 × 13)1/2
Question
x+5/x+2 - x+1/x²+2x
Answer:
= (x² - 4x - 1)/[x (x+2)]
= (x² - 4x - 1)/[x² + 2x]
Step-by-step explanation:
x + 5/x + 2 - x + 1/x² + 2x
We factorise the second denominator to give us :
x + 5/x + 2 - x + 1/x(x + 2)
We find the L.C.M of both denominators which is x(x+2).
[x(x + 5)-(x + 1)] / (x (x + 2))
Expand the bracket
=[x² +5x - x -1] / [x (x + 2)]
=(x² - 4x - 1) / [x (x + 2)]
= (x² - 4x - 1)/ [x (x + 2)]
= (x² - 4x - 1) / [x² + 2x]
<h3>The dimensions of the gym floor could be 150 feet by 120 feet</h3><h3>The dimensions of the gym floor could be 225 feet by 180 feet</h3>
<em><u>Solution:</u></em>
Given that,
The dimensions of the swimming pool and the gym are proportional
The pool is 75 feet long by 60 feet wide
To find: set of possible dimensions for the gym
To determine the possible dimensions for the gym, you would use the same number to multiply both 75 and 60
<em><u>One set of dimensions are:</u></em>
75 x 2 = 150
60 x 2 = 120
The dimensions of the gym floor could be 150 feet by 120 feet
<em><u>Other set of dimensions:</u></em>
75 x 3 = 225
60 x 3 = 180
The dimensions of the gym floor could be 225 feet by 180 feet
