Graph the system of linear inequalities on the coordinate plane.
Shade the solution to the system of inequalities.
Pick a point and show your solution is correct is given below
Step-by-step explanation:
1.When you are graphing inequalities, you will graph the ordinary linear functions just like we done before. The difference is that the solution to the inequality is not the drawn line but the area of the coordinate plane that satisfies the inequality.
2.The linear inequality divides the coordinate plane into two halves by a boundary line (the line that corresponds to the function). One side of the boundary line contains all solutions to the inequality
3.The boundary line is dashed for > and < and solid for ≥ and ≤.
4.Rearrange the equation so "y" is on the left and everything else on the right.
Plot the "y=" line (make it a solid line for y≤ or y≥, and a dashed line for y< or y>)
Shade above the line for a "greater than" (y> or y≥) or below the line for a "less than" (y< or y≤).
5The graph of an inequality in two variables is the set of points that represents all solutions to the inequality. A linear inequality divides the coordinate plane into two halves by a boundary line where one half represents the solutions of the inequality.
No solution; 14/2 = 7; 7^2 = 49; 49 < 120
the 2 numbers that add up to 14 that would give the largest product is less than 120
maybe you mean 120 is negative?
idk i might be wrong
The given complex number is
z = 1 + cos(2θ) + i sin(2θ), for -1/2π < θ < 1/2π
Part (i)
Let V = the modulus of z.
Then
V² = [1 + cos(2θ)]² + sin²(2θ)
= 1 + 2 cos(2θ) + cos²2θ + sin²2θ
Because sin²x + cos²x = 1, therefore
V² = 2(1 + cos2θ)
Because cos(2x) = 2 cos²x - 1, therefore
V² = 2(1 + 2cos²θ - 1) = 4 cos²θ
Because -1/2π < θ < 1/2π,
V = 2 cosθ PROVEN
Part ii.
1/z = 1/[1 + cos2θ + i sin 2θ]
The denominator is
Therefore
The real part of 1/ = 1/ (constant).
Answer:
3 is to 12, 5 is to 50, 7 is to 14, and 11 is to 22.
Step-by-step explanation:
well taking into consideration the natural mixing of water, you should get 0.5x the concentration of salt