Trunk flexor muscles. Hopes this helps.
I believe that the best answer to the choices given in your question is are the following:sea water<span>carbonic acid</span>Thank you for posting here at Brainly.I hope I have answered your question. Have a nice day ahead.
Anions are negatively charged particles. The water molecule is a polar molecule, that means that, it is partly positive and partly negative. The oxygen atoms in the water molecules are more electronegative more than the hydrogen atoms and they draw the shared electron nearer to themselves than the hydrogen atoms; this make them to be slightly negatively charged while the hydrogen atom is slightly positively charged.
Therefore in solution, the anions would be attracted toward the hydrogen atom that is slightly positive while the cations will be attracted to oxygen atom that is slightly negative.
Answer:
A seamount is a mountain that is formed at a hotspot, large enought to be seen above the ocean's surface
Answer:
0.0177
Explanation:
Cystic fibrosis is an autosomal recessive disease, thereby an individual must have both copies of the CFTR mutant alleles to have this disease. The Hardy-Weinberg equilibrium states that p² + 2pq + q² = 1, where p² represents the frequency of the homo-zygous dominant genotype (normal phenotype), q² represents the frequency of the homo-zygous recessive genotype (cystic fibrosis phenotype), and 2pq represents the frequency of the heterozygous genotype (individuals that carry one copy of the CFTR mutant allele). Moreover, under Hardy-Weinberg equilibrium, the sum of the dominant 'p' allele frequency and the recessive 'q' allele frequency is equal to 1. In this case, we can observe that the frequency of the homo-zygous recessive condition for cystic fibrosis (q²) is 1/3200. In consequence, the frequency of the recessive allele for cystic fibrosis can be calculated as follows:
1/3200 = q² (have two CFTR mutant alleles) >>
q = √ (1/3200) = 1/56.57 >>
- Frequency of the CFTR allele q = 1/56.57 = 0.0177
- Frequency of the dominant 'normal' allele p = 1 - q = 1 - 0.0177 = 0.9823
