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3 years ago

7

Create three different expressions that are each equal to 20. Each expression should include only these three numbers: 4, -2, an

d 10.

1 answer:

Archy [21]3 years ago

3 0

Answer:

Step-by-step explanation:

you could do;

10 x -2 = 20

-2 x (-2) x 10 divided by (-2) + 10 + 10 + 10 +10 =20

4 + 4 - 10 x -2 - 4 - 4 = 20

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Express the radical using the imaginary unit i

valentinak56 [21]

Answer:

$=\pm i\sqrt{66}$

Step-by-step explanation:

So we have:

$\pm\sqrt{-66}$

This is the same as:

$=\pm\sqrt{66\cdot-1}$

Separate:

$=\pm\sqrt{66}\cdot\sqrt{-1}$

Replace the second term with i:

$=\pm i\sqrt{66}$

The square root of 66 cannot be simplified.

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3 years ago

What number in 328 is in the tenths place

docker41 [41]

Answer:

2

Step-by-step explanation:i believe hope it helps:)

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3 years ago

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Alex73 [517]

Answer:

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Step-by-step explanation:

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3 years ago

I need to know the improper fractions answers for:

zmey [24]

Answer:

Part 1) $x=\frac{15}{2}\ units$

Part 2) $z=\frac{15\sqrt{3}}{2}\ units$

Part 3) $y= \frac{15\sqrt{3}}{4}\ units$

Part 4) $b= \frac{45}{4}\ units$

Step-by-step explanation:

step 1

Find the value of x

In the large right triangle

$cos(60^o)=\frac{x}{15}$ ----> by CAH (adjacent side divided by the hypotenuse)

Remember that

$cos(60^o)=\frac{1}{2}$

substitute

$\frac{1}{2}=\frac{x}{15}$

solve for x

$x=\frac{15}{2}\ units$ ---> improper fraction

step 2

Find the value of z

In the large right triangle

Applying the Pythagorean Theorem

$15^2=x^2+z^2$

substitute the value of x

$15^2=(\frac{15}{2})^2+z^2$

solve for z

$z^2=15^2-(\frac{15}{2})^2$

$z^2=225-\frac{225}{4}$

$z^2=\frac{675}{4}$

$z=\frac{\sqrt{675}}{2}\ units$

simplify

$z=\frac{15\sqrt{3}}{2}\ units$

step 3

Find the value of y

In the right triangle of the right

$sin(30^o)=\frac{y}{z}$ ---> by SOH (opposite side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$sin(30^o)=\frac{1}{2}$

so

$\frac{1}{2}=y:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{1}{2}= \frac{2y}{15\sqrt{3}}$

$y= \frac{15\sqrt{3}}{4}\ units$

step 4

Find the value of b

In the right triangle of the right

$cos(30^o)=\frac{b}{z}$ ---> by CAH (adjacent side divided by the hypotenuse)

substitute the given values of y and z

Remember that

$cos(30^o)=\frac{\sqrt{3}}{2}$

so

$\frac{\sqrt{3}}{2}=b:\frac{15\sqrt{3}}{2}$

solve for y

$\frac{\sqrt{3}}{2}= \frac{2b}{15\sqrt{3}}$

$b= \frac{45}{4}\ units$

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3 years ago

For the function f(x) = -(x + 1)2 + 4, identify the vertex, domain, and range.

Studentka2010 [4]

f ( x ) = - ( x + 1)^2 + 4

_____________________

Vertex = ( - 1 , 4 )

♡♡♡♡♡♡♡♡♡♡♡♡

Domain = R

♡♡♡♡♡♡♡♡♡♡♡♡

Range = ( - infinite , 4 ]

3 0

3 years ago