There has been two reasons to hypothesis for distracting weather events. One reason is they might’ve been in where the disaster spawns such as a ocean they’re next to. Another reason is if they are. Another reason being the disasters slowly getting dangerous over time and affecting the earth today.
I tried. Hope it helps :)
Answer:
E) Either anaphase I or II
Explanation:
Failure of segregation of homologous chromosomes during anaphase I or failure of segregation of sister chromatids during anaphase II leads to the presence of the abnormal number of chromosomes in resultant gametes. In the given example, the egg mother cell with 48 chromosomes (24 pairs) would enter meiosis I but the failure of one pair of homologous chromosomes to segregate from each other followed by normal meiosis II would result in the formation of two gametes with one extra chromosome and two gametes with one less chromosome.
On the other hand, if the nondisjunction occurs at anaphase II of meiosis II, two normal gametes, one gamete with one extra chromosome and one gamete with one less chromosome will be formed. Therefore, nondisjunction at anaphase I or anaphase II would have resulted in the production of eggs with one extra chromosome.
Answer:
Yes, you are correct! C,D and E are correct
<span><span>Protista
Plantae
Fungi
Animilia
Eubacteria
</span> Archaebacteria</span>
<span>1) The probability of F2 seed chosen at random will be yellow is the same as asking about the probability of forming a yellow seed in that generation. The answer is 3/4 (75%) because 1/4 = 25% GG is homozygous dominant and the rest 2/4 = 50% Gg are heterozygous.
2) In the F2 generation there are
two genotypes that will breed true, which is homozygotic genotypes: GG and gg. But of these two, only one of
them is yellow. The answer is 1/3 because from all the yellow seeds that resulted (GG, Gg and gG) only one has the genotype for true breeding.
3) The probability of taking out three seeds in which a least one is yellow can be calculated by subtracting the only
probability that doesn't fit the criterion, which is taking out a green seed 3 times:

= 1/64.
Then substract that to 1

=

4) there are three possible groupings in which the green is taken once and the yellow seeds taken twice. The first possibility (follow the example) is the green being the first to come out, another possibility is being the second and the last possibility is being taken in the third time.
For example, Green yellow yellow- probability : </span>
<span><span><span>

</span> = 9/64
This is one possibily, but since there are 3, multiply it by 3 and you obtain the final answer:2</span>7/64. </span>