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strojnjashka [21]
3 years ago
15

Find the area of the triangle

Mathematics
1 answer:
deff fn [24]3 years ago
3 0
A=hb*b/2
3yd*8yd= 24yd 
now divide that by 2
12yards is the answer
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Four equivalent expressions for 24x-8x
dolphi86 [110]

1: 8(3x-x)

2: 16x

3: 4(4x)

4: 8(2x)


7 0
4 years ago
Find the x value 4x-28 9x
andriy [413]

Answer: -5.6

Step-by-step explanation:

Simplifying

(4x + -28) = 9x

Reorder the terms:

(-28 + 4x) = 9x

Remove parenthesis around (-28 + 4x)

-28 + 4x = 9x

Solving

-28 + 4x = 9x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-9x' to each side of the equation.

-28 + 4x + -9x = 9x + -9x

Combine like terms: 4x + -9x = -5x

-28 + -5x = 9x + -9x

Combine like terms: 9x + -9x = 0

-28 + -5x = 0

Add '28' to each side of the equation.

-28 + 28 + -5x = 0 + 28

Combine like terms: -28 + 28 = 0

0 + -5x = 0 + 28

-5x = 0 + 28

Combine like terms: 0 + 28 = 28

-5x = 28

Divide each side by '-5'.

x = -5.6

Simplifying

x = -5.6

5 0
3 years ago
Write each decimal as a fraction <br> .07<br> .051<br> .473<br> .27<br> .5.37<br> .16.49
Colt1911 [192]

Answer:

7/10

51/100

473/1000

27/100

537/1000

1649/10000

Step-by-step explanation:

im curious about what the dots are in .16.49 and .5.37, why are there two dots?

3 0
3 years ago
Given that cos 63°≈ 0.454, enter the sine of a complementary angle.<br> sin
jek_recluse [69]

Answer:

\cos(63^\circ) is the same as \sin(27^\circ) by co-function identities

Step-by-step explanation:

Remember that complementary angles add up to 90°. The angle that i s complementary to 63° is 27°.

Also recall the co-function identities:

  • sin (90° – x) = cos x
  • cos (90° – x) = sin x

This means that \cos(90^\circ-27^\circ)=\sin(27^\circ)\approx0.454.

4 0
2 years ago
Please answer as well?
dimulka [17.4K]

Answer:

I think it is the 3rd one

Step-by-step explanation:

I hope it is. Sorry if not, I tried.

8 0
3 years ago
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