It is given that the sample size is 17.
So degrees of freedom is 16.
The confidence level is 80%.
Use the t table or a tool to find the critical t value as below:
The one tail t value for 80 percent confidence is 0.865 using t table.
So the critical value is 0.865.
Answer:
median
Step-by-step explanation:
the median would make the score as good as possible, because there could be possible outliers. this really depends on if there are outliers or not. here is an example of what i need:
say you are trying to show your parents your grades:
here are your scores:
38, 88, 90, 91, 93, 95, 100
the median would be 91, which looks better.
the mean would be 85.
even though a <em>majority</em> of your grades are good, the one 38 makes the average go down. therefore, the median is a better advertiser.
In my opinion the answer is <span>m2 – 100 = –99
proof
</span>m2 – 100 =<span>(m – 10)(m + 10)
for eg. m=1, </span>(-9)(11)= <span>–99</span>
The answer is 3. -2i square root of 2
-2 (Rise over run) goes up 2 and over 1 and the line is going down