Answer:
Diameter of the pipe ≈ 6.77 ft
Step-by-step explanation:
Volume of a cylinder = πr²h
Here, r = Radius of the cylindrical pipe
h = Length of the pipe
Volume of the pipe = 900 ft³
Length of the pipe = 25 ft
By substituting the given values in the formula,
900 = π(r)²(25)
r² = 
r = √11.459
r = 3.385
Diameter = 2(radius)
= 2(3.385)
= 6.77 ft
Answer:
46.08 inches
Step-by-step explanation:
2.5 pounds weight stretches a spring to 18 inches
A pound weight will stretch 18inches divided by 2.5 pounds
= 7.2 inches
6.4 pounds will stretch = 7.2 X 6.4
= 46.08 inches
9514 1404 393
Answer:
(2) 72°
Step-by-step explanation:
In this geometry, the angle at the tangent is half the measure of the intercepted arc.
∠CBD = (arc BD)/2 = 144°/2
∠CBD = 72°
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<em>Additional comment</em>
Consider a point X anywhere on long arc BD. The inscribed angle at X will have half the measure of short arc BD, so will be 144°/2 = 72°. This is true regardless of the position of X on long arc BD. Now, consider that X might be arbitrarily close to point B. The angle at X is still 72°.
As X approaches B, the chord XB approaches a tangent to the circle at B. Effectively, this tangent geometry is a limiting case of inscribed angle geometry.
I tried my best to interpretate what you wrote. So I'm gonna attach a picture of what I came up with and my work. If you have any questions then just ask. :)