A numerical or constant quantity place before and multiplying the variable in an algebraic expression
Answer:
3x + 6y = 64.50________equation 1
9x + 8y = 106.00_______equation 2
Price of a bag of popcorn is $3(300 cents) WHILE the price of one drink is $8.75(875 cents)
Step-by-step explanation:
The question here says that Kayden and Carter go to the movie theater and purchase refreshments for their friends.
Kayden spends a total of $64.50 on 3 bags of popcorn and 6 drinks.
Carter spends a total of $106.00 on 9 bags of popcorn and 8 drinks.
Now let's assume that the price of each bag of popcorn is X and the price of one drink as Y
It means that
3x + 6y = 64.50________equation 1
9x + 8y = 106.00_______equation 2
Make "x" the subject of the formula in equation 1
3x = 64.50 - 6y
X = (64.50 - 6y)/3
Apply the above in equation 2 and we have
9[ (64.50 - 6y)/3] + 8y = 106
9(21.5 - 2y) +8y = 106
193.5 - 18y + 8y = 106
193.5 - 10y = 106
Y= (193.5 - 106)/10
Y= $8.75 (price of one drink)
Now substitute Y = 8.75 in equation 1
3x + 6y = 64.50
3x + 6(8.75) = 64.50
3X = 64.50 - 52.5
X = 12/3
X = 3
Why must you give me a hard one *smh* -v-''
The answer is 128,900 :D
add me on disc its not letting me explain what i wanted to explain its Andrew#6506
Answer:
X=1
Step-by-step explanation:
