Question

The diameter of a basketball rim is 18 inches. A standard basketball has a circumference of 30 inches. What is the distance between the ball and the rim in a shot in which the ball goes exactly in the center of the rim? Show your work.
Please show the steps!! This unit is area, if that helps.

Answer 1

Hello!

First you have to find the circumference of the rim

To find the circumference you use the equation

$C = 2 \pi r$

C is circumferece
r is radius which is half the diameter

Put in the values you know

$C = 2 \pi (9)$

C ≈ 56.55

You subtract the circumference of the rim by the circumference of the ball

56.55 - 30 = 26.55

The answer is 26.55 inches

Hope this helps!

Answer 2

Diameter of the basketball rim = 18 inchesCircumference of the standard basketball = 30 inches
Area of circle = π r² 
Basketball rim = 3.14 * (18/2)² = 3.14 * 9² = 3.14 * 81 = 254.34 in²
Circumference of a circle = 2 π r30 = 2 * 3.14 * rr = 30 / (2*3.14) = 30 / 6.28 = 4.78 inches
Standard basketball = 3.14 * (4.78)² = 3.14 * 22.85 = 71.75 in²
254.34 - 71.75 = 182.59 in²