Answer:
<h2>A. (0,1)</h2>
Step-by-step explanation:
The question lacks the e=required option. Find the complete question below with options.
Which of the following points does not belong to the quadratic function
f(x) = 1-x²?
a.(0,1) b.(1,0) c.(-1,0)
Let f(x) = 0
The equation becomes 1-x² = 0
Solving 1-x² = 0 for x;
subtract 1 from both sides;
1-x²-1 = 0-1
-x² = -1
multiply both sides by minus sign
-(-x²) = -(-1)
x² = 1
take square root of both sides;
√x² = ±√1
x = ±1
x = 1 and x = -1
when x = 1
f(x) = y = 1-1²
y = 1-1
y = 0
when x = -1
f(x) = y = 1-(-1)²
y = 1-1
y = 0
Hence the coordinate of the function f(x) = 1-x² are (±1, 0) i.e (1, 0) and (-1, 0). The point that does not belong to the quadratic function is (0, 1)
The answer is <span>a. $1.75 + $0.25x ≤ $15; x ≤ 53 miles
</span>
x - the number of miles
C - the cab charge
<span>A cab charges $1.75 for the flat fee and $0.25 for each mile: C = 1.75 + 0.25x.
</span><span>Eddie has $15 to spend. So, he cannot spend more than 15 on the cab and the maximum amount he can spend is 15. Therefore:
</span>1.75 + 0.25x ≤ 15
Now, let's solve it:
0.25x ≤ 15 - 1.75
0.25x ≤ 13.25
x ≤ 13.25 / 0.25
x ≤ 53
As there are no parenthesis, Follow PEMDAS and go from left to right
14 x 13 = 182
182/9 = 20.22
20.22 + 8 = 28.22
28.22 is your answer
hope this helps
