Question

7,,,,,,,,,,,,,,,,,,,,please help

Answer 1

Answer:

1

Step-by-step explanation:

The given expression is

$\frac{2^{\frac{11}{2} }\times 2^{-7}\times 2^{-5}}{2^3\times 2^{\frac{1}{2} }\times 2^{-10}}$

Recall and use

$a^m\times a^n=a^{m+n}$

$\frac{2^{\frac{11}{2} -7-5}}{ 2^{3+\frac{1}{2} -10}}$

$\frac{2^{-\frac{13}{2}}}{ 2^{-\frac{13}{2}}}$

Same bases are dividing, so we write one base and subtract the exponent.

$2^{-\frac{13}{2}+\frac{13}{2}}$

$2^0=1$