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tatiyna
3 years ago
8

7,,,,,,,,,,,,,,,,,,,,please help

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer:

1

Step-by-step explanation:

The given expression is

\frac{2^{\frac{11}{2} }\times 2^{-7}\times 2^{-5}}{2^3\times 2^{\frac{1}{2} }\times 2^{-10}}

Recall and use

a^m\times a^n=a^{m+n}

\frac{2^{\frac{11}{2} -7-5}}{ 2^{3+\frac{1}{2} -10}}

\frac{2^{-\frac{13}{2}}}{ 2^{-\frac{13}{2}}}

Same bases are dividing, so we write one base and subtract the exponent.

2^{-\frac{13}{2}+\frac{13}{2}}

2^0=1

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3 years ago
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3 years ago
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4 years ago
x = y + 4 2x - 3y = -2 What is the solution to the system of equations? A) (6, 10) B) (9, 5) C) (10, 6) D) (14, 10)
Oksana_A [137]

Answer:

D

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