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3 years ago

I need some help please

Mathematics

1 answer:

Nadya [2.5K]3 years ago

4 0

Answer: I: (3, +infinity) D: (-infinity, 3) (this is the fourth answer)

Step-by-step explanation: The graph is decreasing left to right until 3, and begins to increase from left to right beginning at 3.

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What value of x makes 10x = 350 a true statement? A) 35 B) -35 C) -3.5 D) 3.5

Juli2301 [7.4K]

The answer is 35
choice A

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3 years ago

which expression is equivalent to 2m(3/2m+1) +3 (5/3m-2) ? A .3m^2+5m-1 B. 3/4m^2 +23/9m-6 C. 3m^2+7m-6 D. 3/4m^2+5/9m-1 please

horrorfan [7]

Answer:

Step-by-step explanation:

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4 years ago

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A parabola can be drawn given a focus of (1, -7) and a directrix of y = 1. Write the

Paha777 [63]

Answer:

Step-by-step explanation:

focus (1 , -7) ⇒ a = 1 & b = -7

y = 1 ⇒ c = 1

Equation of parabola :

(x - a)² + (y - b)² = (y - c)²

(X - 1)² + (y + 7)² = (y - 1)²

Now, expand.

x² - 2x + 1 + y² + 2*7*y + 7² = y² - 2*y*1 + 1

x² - 2x + 1 + y² - 14y + 49 = y² - 2y +1

x² - 2x + 1 + y² - 14y + 49 - y² + 2y - 1 = 0

x² - 2x + y² - y² - 14y + 2y + 1 + 49 - 1 = 0

x² - 2x - 12y + 49 = 0

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3 years ago

77 is 22.3% of what number

Elza [17]

Answer:

345.29

Step-by-step explanation:

77 divided by .223 = 345.2914798

6 0

4 years ago

"Find an integer, x, such that 5, 10, and x represent the lengths of the sides of an acute triangle.

Contact [7]

A, b, c - the lengths of the sides of the triangle
and a ≤ b ≤ c
then:
a + b > c and if the triangle is an acute triangle then a² + b² > c².

$1^o\\5\leq10\leq x\\\\\left\{\begin{array}{ccc}5+10 \ \textgreater \ x\\5^2+10^2 \ \textgreater \ x^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x^2 \ \textless \ 125\end{array}\right\to\left\{\begin{array}{ccc}x \ \textless \ 15\\ x \ \textless \ \sqrt{125}\approx11.1\end{array}\right\\\\\boxed{x=11}\\\\2^o\\5\leq x\leq10\\\\\left\{\begin{array}{ccc}5+x \ \textgreater \ 10\\ 5^2+x^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x=9}$

$3^o\\x\leq5\leq10\\\\\left\{\begin{array}{ccc}x +5 \ \textgreater \ 10\\ x^2+5^2 \ \textgreater \ 10^2\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x^2 \ \textgreater \ 75\end{array}\right\to\left\{\begin{array}{ccc}x \ \textgreater \ 5\\ x \ \textgreater \ \sqrt{75}\approx8.7\end{array}\right\\\boxed{x\in\O}\\\\Answer:\boxed{x=9\ or\ x=11}\to your\ answer:\boxed{\boxed{x=11}}$

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4 years ago

Read 2 more answers