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3 years ago

14

I need help from someone please?!

1 answer:

Andreyy893 years ago

3 0

3)
(x/3)+(2/5)
(5x/15)+(6/15)
(5x+6)/15

4)
(2/x)+(3/7)
(14/7x)+(3x/7x)
(3x+14)/(7x)

5)
(x/2)+(1/3)+(x/4)
(6x/12)+(4/12)+(3x/12)
(9x+4)/12

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In a class of 40 students, 5 like neither Nokia nor

Vikki [24]

Answer:

No student liked only Nokia

Step-by-step explanation:

The information can be illustrated as shown on the Venn diagram.

The number of students who liked only Nokia is x.

The sum of all regions in the Venn diagram should be 40.

We add all to get:

$5 + 5 + 30 + x = 40$

$40 + x = 40$

$x = 40 - 40$

$x = 0$

Therefore no one liked only Nokia

8 0

3 years ago

ycow [4]

Answer:

$11$ bushels of apples were sold

Step-by-step explanation:

Let

x----> bushels of peaches

y----> bushels of apples

we know that

$7x+6y=346$ -----> equation A

$x=y+29$ -----> equation B

substitute equation B in equation A and solve for y

$7(y+29)+6y=346$

$7y+203+6y=346$

$13y=346-203$

$13y=143$

$y=143/13=11$

5 0

3 years ago

(3m^3- 1/2 y) (3m^w - 1/2y)

Brilliant_brown [7]

We use FOIL method to multiply this out. First termsOuter termsInner termsLast terms Product = (3m3 * 3m3) + (3m3 * -1/2y) + (-1/2y * 3m3) + (-1/2y * -1/2y) Product = 9m6 - (3/2)m3y - (3/2)m3y + (1/4)y2 <span>Product = 9m6 - 3m3y + (1/4)y<span>2</span></span>

6 0

3 years ago

A bakery sold 2,070 loaves of whole-wheat bread in July. In all, the bakery sold 9,000 loaves of bread that month. What percent

Crank

Answer:

2070 / 6930 = 0.2987.....x 100 = 29.87%

3 0

3 years ago

Solve the following system of equations. (Hint: Use the quadratic formula.) f(x) = 2x² 3x g(x)=-3x² + 20 (0.-10) and (1, 17) (-2

jasenka [17]

The solution of the system of equation is the intersection point of the two quadratic equations, so we need to equate both equations, that is,

$2x^2-3x-10=-3x^2+20$

So, by moving the term -3x^3+20 to the left hand side, we have

$5x^2-3x-30=0$

Then, in order to solve this equation, we can apply the quadratic formula

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

In our case, a=5, b=-3 and c=-30. So we get

$x=\frac{3\pm\sqrt{(-3)^2-4(5)(-30)}}{2(5)}$

which gives

$\begin{gathered} x=2.76779 \\ and \\ x=-2.16779 \end{gathered}$

By substituting these points into one of the functions, we have

$f(2.76779)=-2.982$

and

$f(-2.16779)=5.902$

Then, by rounding these numbers to the nearest tenth, we have the following points:

$\begin{gathered} (2.8,-3.0) \\ and \\ (-2.2,5.9) \end{gathered}$

Therefore, the answer is the last option

4 0

1 year ago