C r = (n!)/(r!(n-r)!)
9 C 3 = (9!)/(3!*(9-3)!)
9 C 3 = (9!)/(3!*6!)
9 C 3 = (9*8*7*6!)/(3!*6!)
9 C 3 = (9*8*7)/(3!)
9 C 3 = (9*8*7)/(3*2*1)
9 C 3 = (504)/(6) 9 C 3 = 84
Answer:
16
Step-by-step explanation:
Answer:
Step-by-step explanation:
The equation of line having slope 
and passing through 
.
Correct Answer:
Option D (12, -5)
In Quadrant IV, the x-component of the point is positive and the y-component is negative. From the given points, option D contains the point with a positive x-component i.e.12 and negative y-component i.e -5. Therefore, this point lies in Quadrant IV.
Solution:
<u>Note that:</u>
- AB = EF
- BC = EG = 6x - 8
- 7x - 19 = 2x + 11
- Perimeter of triangle: 24 + 2x + 11 + 6x - 8
<u>Solving for x:</u>
- 7x - 19 = 2x + 11
- => 7x - 2x = 19 + 11
- => 5x = 30
- => x = 30/5 = 6
<u>Substitute the value of x into the expression (24 + 2x + 11 + 6x - 8): </u>
- 24 + 2x + 11 + 6x - 8
- => 24 + 2(6) + 11 + 6(6) - 8
- => 24 + 12 + 11 + 36 - 8
- => 24 + 12 + 3 + 36
- => 75 units
The perimeter of the triangle ABC is 75 units.
