All categories

3 years ago

What is the answer to -4.3x + 12 + 15.1x = 33.6?

Mathematics

1 answer:

Mashutka [201]3 years ago

6 0

Answer:

10.8x +45.6

Step-by-step explanation:

am smart

You might be interested in

Plz help me answer the last 5 questions the first 3 pics is the article to help answer the question I have very little time so I

nadezda [96]

The papers are to blurry hard to read cdn you repost them

4 0

3 years ago

Find two rational numbers such that the sum of the first and three times the second is 5 and the sum of second and two times the

masha68 [24]

Answer: E. (x,y) = (-19/5, 3/5)

Step-by-step explanation:

7 0

3 years ago

He price of a desktop computer decreases from $1360 to $1020 what is the percentage decreasing in its price ?

In-s [12.5K]

Answer:

Dec % = 340/1360*100= 25%

3 0

3 years ago

What is the square root of 5 plus the square root of 5

Charra [1.4K]

Answer:

That would be approximately 4.47.

6 0

3 years ago

Area of a triangle with points at (-9,5), (6,10), and (2,-10)

Ann [662]

First we are going to draw the triangle using the given coordinates.
Next, we are going to use the distance formula to find the sides of our triangle.
Distance formula: $d= \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

Distance from point A to point B:
$d_{AB}= \sqrt{[6-(-9)]^2+(10-5)^2}$
$d_{AB}= \sqrt{(6+9)^2+(10-5)^2}$
$d_{AB}= \sqrt{(15)^2+(5)^2}$
$d_{AB}= \sqrt{225+25}$
$d_{AB}= \sqrt{250}$
$d_{AB}=15.81$

Distance from point A to point C:
$d_{AC}= \sqrt{[2-(-9)]^2+(-10-5)^2}$
$d_{AC}= \sqrt{(2+9)^2+(-10-5)^2}$
$d_{AC}= \sqrt{11^2+(-15)^2}$
$d_{AC}= \sqrt{121+225}$
$d_{AC}= \sqrt{346}$
$d_{AC}= 18.60$

Distance from point B from point C
$d_{BC}= \sqrt{(2-6)^2+(-10-10)^2}$
$d_{BC}= \sqrt{(-4)^2+(-20)^2}$
$d_{BC}= \sqrt{16+400}$
$d_{BC}= \sqrt{416}$
$d_{BC}=20.40$

Now, we are going to find the semi-perimeter of our triangle using the semi-perimeter formula:
$s= \frac{AB+AC+BC}{2}$
$s= \frac{15.81+18.60+20.40}{2}$
$s= \frac{54.81}{2}$
$s=27.41$

Finally, to find the area of our triangle, we are going to use Heron's formula:
$A= \sqrt{s(s-AB)(s-AC)(s-BC)}$
$A=\sqrt{27.41(27.41-15.81)(27.41-18.60)(27.41-20.40)}$
$A= \sqrt{27.41(11.6)(8.81)(7.01)}$
$A=140.13$

We can conclude that the perimeter of our triangle is 140.13 square units.

3 0

3 years ago