The sum of 3 consecutive integers is 120. What is the greatest of these integers? HELP ME IT'S DUE TODAY!!!
1 answer:
Answer:
<h3>
41</h3>
Step-by-step explanation:
The consecutive integers are increasing by 1
x ← the smallest integer
x+1 ← the middle integer
x+1+1 = x+2 ← the largest integer
x + x+1 + x+2 = 120
3x + 3 = 120
÷3 ÷3
x + 1 = 40
-1 -1
x = 39
x+2 = 39 + 2 = 41
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