Question

The sum of 3 consecutive integers is 120. What is the greatest of these integers? HELP ME IT'S DUE TODAY!!!

Answer 1

Answer:

              41

Step-by-step explanation:

The consecutive integers are increasing by 1

x ← the smallest integer

x+1 ← the middle integer

x+1+1 = x+2   ← the largest integer

x + x+1 + x+2 = 120

   3x + 3 = 120

      ÷3        ÷3

      x + 1 = 40

         -1       -1

        x = 39

x+2 = 39 + 2 = 41