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PIT_PIT [208]
2 years ago
10

Which expression is equivalent to?

Mathematics
2 answers:
AlekseyPX2 years ago
7 0

Answer:

D

Step-by-step explanation:

multiply the inside by -0.5

iogann1982 [59]2 years ago
6 0

Answer:

-3\left(x-2\right)

Step-by-step explanation:

\frac{-1}{2}\left(6x-12\right)=\frac{\left(-1\right)\left(6x-12\right)}{2}==-\frac{\left(6x-12\right)}{2}=-3\left(x-2\right)

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When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
2 years ago
What is 2x . 5x . 79x
murzikaleks [220]

Answer:

790x

may i am correct

srt for wrong answer

3 0
2 years ago
The volume of a solid is measured in units cubed. True False
weeeeeb [17]
I think the answer would be true
4 0
3 years ago
Read 2 more answers
13. Given: AB//DC, Prove: Triangle ABE is congruent to Triangle DCE please help! I am so far behind on my work right now I will
scoundrel [369]
2.Alternate Interior angles theorem.
They given angles are alternate and interior when compared to each other, so they are congruent.  
3 Vertical angles theorem.
The two angles are vertical angles and are not congruent. 
4 Angle-Angle Similarity Postulate. 
Because there are two corresponding angles that are congruent they are similar triangles by the angle-anlge similarity postulate.
7 0
3 years ago
The domain of the following relation has how many elements?
Ivahew [28]

Answer:

b. 1

Step-by-step explanation:

All first coordinates are 1/2.

Answer: b. 1

5 0
2 years ago
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