3 years ago

Needs help ASAP please

Mathematics

1 answer:

dlinn [17]3 years ago

8 0

4) the information on this problem is that the she wants to charge $3-$4 for her baseballs and there are 28 players

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The measured dimensions of a rectangle are 7m by 4m to the nearest whole unit. Find the minimum and maximum possible areas of th

Monica [59]

Answer:

Maximum area = Minimum area = 28 m².

Step-by-step explanation:

The length and the width of the rectangle are measured to be 7 m and 4 m respectively to the nearest whole number.

We have to find the maximum and minimum possible areas of the rectangle.

The maximum or minimum area is calculated only when length or width or both can vary and then only for a certain value of length and width the area becomes maximum or minimum.

So, the maximum and minimum area of the rectangle will be the same i.e. (7 × 4) = 28 m². (Answer)

3 0

3 years ago

The perimeter of a square in which A=169cm square root 2?

sergey [27]

I'm guessing you mean:
$A = 169 \sqrt{2}$

If not, correct me.

So, then the perimeter of a square is just 4*A, which in this case would be:
$4(169 \sqrt{2}) = 676 \sqrt{2}$

And that would be your answer: $676 \sqrt{2}$ units²