Answer:
3.
Step-by-step explanation:
Find the midpoint of BC:
midpoint = (-1+5)/2, (2-2)/2 = (2, 0).
The slope of BC = (2 - -2) / (-1-5) = -2/3.
Find the equation of the right bisector of BC:
The slope = -1 / -2/3 = 3/2.
y-y1 = m(x-x1)
y - 0 = 3/2(x - 2)
y = 3/2x - 3.
Now find the equation of the median through C:
The midpoint of AB = (1 - 1)/2, (4+2)/2
= (0, 3).
The equation of the median:
The slope = (-2-3) / (5-0)
= -1.
The equation is:
y - 3 = -1(x - 0)
y -3 = -x.
Now we find the point of intersection by solving the 2 equations:
y - 3 = -x
y = 3/2x - 3
y = -x + 3
So:
3/2x - 3 = -x + 3
3/2x + x = 6
5/2 x = 6
x = 12/5.
y = -12/5 + 3
= -12/5 + 15/5
= 3/5.
The sum of the coordinates = 12/5 + 3 /5
= 15/5
= 3.
Answer:
Step-by-step explanation:
For this sort of problem, there can be an infinite number of answers.
It can be convenient to choose one of the simpler answers by looking at the operations that are performed on the variable. Here, you have ...
- 2 multiplies it
- 4 is added to the product
- the square root is taken
- 8 is divided by that root
You can work from the bottom up and define the outer function (f(x)) to be any of these operations. In our answer above, we have elected to include the "square root" and the "8 divided by that root" in our definition of f.
Then our function g takes care of the other operations.
The volume of the pyramid would be 2406.16 cubic cm.
<h3>How to find the volume of a square-based right pyramid?</h3>
Supposing that:
The length of the sides of the square base of the pyramid has = b units
The height of the considered square-based pyramid = h units,
The pyramid below has a square base.
h = 24.4 cm
b = 17.2 cm
Then, its volume is given by:


Therefore, the volume of the pyramid would be 2406.16 cubic cm.
Learn more about pyramid;
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Answer:
for q4 it 3 but q5 ibk.. .............