Solve for u 3(u+3)=9
1 answer:
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Answer:
Part 1) The axis of symmetry is x=2
Part 2) The vertex is the point (2,8)
Part 3) The domain is all real numbers
Part 4) The range is all real numbers less than or equal to 8
Step-by-step explanation:
we have
This is a vertical parabola open downward (because the leading coefficient is negative)
The vertex represent a maximum
step 1
Find the vertex
Convert the quadratic equation in vertex form
Factor -2 leading coefficient
Complete the square
rewrite as perfect squares
so
The vertex is the point (2,8)
step 2
Find the axis of Symmetry
we know that
In a vertical parabola, the axis of symmetry is equal to the x-coordinate of the vertex
the vertex is the point (2,8)
therefore
The axis of symmetry is x=2
step 3
Find the domain
The domain of the quadratic equation is the interval ------> (-∞,∞)
The domain is all real numbers
step 4
Find the range
The range of the quadratic equation is the interval ------> (-∞,8]
The range is all real numbers less than or equal to 8
