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2 years ago

Solve for u 3(u+3)=9

Mathematics

1 answer:

Elanso [62]2 years ago

7 0

3u+ 9 is the right answer, since thier not like terms you can’t add them

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HURRRRYYYYYYY PLEASE Write the equation of the line that passes through the points (-8,-1) and (5,−7). Put your answer in full

Zinaida [17]

Answer:

y + 8 = 2x + 2

Step-by-step explanation:

Use the points given to find the slope. Divide the difference in y-values by the difference in x-values.

(-1) - (-7) = 6

5 - (-8) = 3

6/3 = 2

The slope is 2.

Now, pick one of the points to put in point-slope form. It doesn't matter which. You will get the right answer either way. I will use (-1, -8).

y - y₁ = m(x - x₁)

y - (-8) = 2(x - (-1))

y + 8 = 2(x + 1)

y + 8 = 2x + 2

3 0

2 years ago

Evaluate <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%5E%7B-2%7Dx%5E%7B-3%7Dy%5E%7B5%7D%20%7D" id="TexFormula1" title="\

Irina18 [472]

Answer:

$\bf C)\: -\cfrac{1}{32}$

Step-by-step explanation:

$\tt \cfrac{1}{2^{-2}x^{-3}y^5}$

$\tt x=2\\y=-4$

Substitute ''x'' with '2' & 'y' with "-4":-

$\tt \cfrac{1}{2^{-2}\times \:2^{-3}\left(-4\right)^5}$

First let's solve $\tt 2^{-2}\times \:\:2^{-3}\left(-4\right)^5$

$\tt 2^{-2}\times \:2^{-3}=\boxed{\cfrac{1}{32} }$

$\tt \cfrac{1}{32}\left(-4\right)^5$

Calculate exponents:- -4^5= -1024

$\tt \cfrac{1}{32}\left(-1024\right)$

Remove parentheses, apply rule:- $\tt a\left(-b\right)=-ab$

$\tt-\frac{1}{32}\times \:1024$

$\tt \cfrac{1}{32}\times \cfrac{1024}{1}$

Apply fraction rule:-

$\tt -\cfrac{1\times \:1024}{32\times \:1}$

$\tt \cfrac{1024}{32}$

Divide numbers:-

$\tt -32$

Now that we're done factoring the denominator let's bring down the numerator which is ' 1 ':-

$\tt -\cfrac{1}{32}\;\; \bf Answer$

3 0

1 year ago

Read 2 more answers

Order these rational numbers in order from least to greatest 1/5 and -0.4 and -1/4 and 0.5

natita [175]

-0.4, -1/4, 1/5, 0.5

7 0

2 years ago

Which can be a next step in the construction of an angle with a side on line l that is congruent to ∠ABC?

8090 [49]

Answer:

The next step is draw a line connecting the point F and the point lies on ray l.

4 0

2 years ago

Solving for matrices

muminat

Answer:

Step-by-step explanation:

The augmented matrix for the system of three equaitons is

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\5&2&-2&|&11\\5&-4&4&|&-7\end{array}\right)$

Multiply the first row by 5, the second row by -3 and add these two rows:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)$

Subtract the third row from the second:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)$

Divide the third row by 6:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)$

Now multiply the third equation by 26 and add it to the second row:

$\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)$

You get the system of three equations:

$\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.$

From the third equation

$z=\dfrac{90}{45}=2.$

Substitute z=2 into the second equation:

$-26y-19\cdot 2=-168\\ \\-26y-38=-168\\ \\-26y=-168+38=-130\\ \\y=\dfrac{130}{26}=5.$

Now substitute z=2 and y=5 into the first equation:

$3x-4\cdot 5-5\cdot 2=-27\\ \\3x-20-10=-27\\ \\3x-30=-27\\ \\3x=-27+30=3\\ \\x=1.$

The solution is (1,5,2)

4 0

2 years ago