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3 years ago

Help please!!!! will Brainly!!!

Mathematics

2 answers:

igor_vitrenko [27]3 years ago

8 0

True :) have a nice day! :) can u make me brainliest? Pls :)? Ty ✨

yuradex [85]3 years ago

5 0

Answer:

true

Step-by-step explanation:

.................

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What is the equation of the line shown in this graph

prisoha [69]

Slope = (2+4)/(1-4) = 6/-3 = -2
passing thru (1.2)
y = mx + b
b = y - mx
b = 2 - (-2)(1)
b = 2 + 2
b = 4

equation
y = -2x + 4

7 0

3 years ago

Evaluate the quotient of 1.05 x 103 and 1 x 103:

Mama L [17]

1.5 * 103= 108.15
103 * 1 = 1
hope i helped

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3 years ago

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How many inches did the height of the plant increase between weeks 3 and 4

Allisa [31]

It increased a total of 4 inches.

6 0

3 years ago

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9Find -18 + (-67). Show your work.

polet [3.4K]

Answer:

-85

Explanation:

Given the mathematical expression:

$-18+(-67)$

First, we recall the product of signs.

$+\times-=-$

So, first, we open the bracket:

$-18+(-67)=-18-67$

We then simplify:

$=-85$

The result is -85.

3 0

1 year ago

Triangle ABC is an isosceles triangle in which side

Shkiper50 [21]

Answer:

Option B.

Step-by-step explanation:

Consider the below figure attached with this question.

It is given that triangle ABC is an isosceles triangle.

From the below figure it is clear that the vertices of triangle are A(-2,-4), B(2,-1) and C(3,-4).

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using this formula, we get

$AB=\sqrt{(2-(-2))^2+(-1-(-4))^2}=\sqrt{16+9}=5$

$BC=\sqrt{(3-2)^2+(-4-(-1))^2}=\sqrt{1+9}=\sqrt{10}$

$AC=\sqrt{(3-(-2))^2+(-4-(-4))^2}=\sqrt{25}=5$

Now,

Perimeter of triangle ABC = AB + BC + AC

$=5+\sqrt{10}+5$

$=10+\sqrt{10}$

So, perimeter of triangle ABC is $10+\sqrt{10}$ units.

Therefore, the correct option is B.

4 0

3 years ago

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