Can someone solve this for me and explain how they solved it !! thanks !

Solve for x. <br><br> Brainlest for anyone who helps!! <br><br> thanks you

gavmur [86]

<h3>Answer: C) 0</h3>

================================================

Explanation:

If points F and E are the midpoints of segment VU and segment ST respectively, then segment FE is the midsegment of the trapezoid. The midsegment is parallel to the bases, and the midsegment's length is found by adding up the bases VS and UT, then dividing by 2.

(VS + UT)/2 = FE

(29 + x+17)/2 = 23 ... plug in given info; isolate x

(x+46)/2 = 23

x+46 = 23*2 ... multiply both sides by 2

x+46 = 46

x = 46-46 ... subtract 46 from both sides

6 0

3 years ago

Javier works in a photo lab and needs to make a reduced copy of a photograph that is 8 inches long. The customer wants the copy

Aleksandr [31]

Javier boss is correct and he should not press it 5 times

5 0

4 years ago

Ed's age is twice that of his brother. When you add Ed's age to his brother's age, you get 36. How old is each brother?

svlad2 [7]

The answer to your question is,

Ed is 27. His brother is 9.

How did I get this answer?

Ed's age is twice that of his brother. So of course, when you divide 36 by 2, you would get 18. They are not twins so this wouldn't be the answer. You need to divide 18 by 2 again. This makes 9. If you add 9 to 27, that makes 36. Which is their ages.

-Mabel <3

6 0

4 years ago

A bowl contains 8 chips: 4 blue and 4 red. Three chips are drawn at random and without replacement from a bowl. What is the prob

PIT_PIT [208]

Answer:

the probability that 3 blue chips ( or red chips) are chosen is P(X=3) = 1/14

Step-by-step explanation:

Since the X= choosing x blue chips, then P(X) follows an hypergeometric distribution , when sampling is done without replacement

P(X=x) = (C,x) * (N-C , n-x) /( N ,n)

where ( ) represents combinations then

N= population size = 8 chips

n = sample size = 3 chips

C = number of blue chips = 4 chips

x= number of blue chips that are chosen = 3 blue chips

replacing values

P(X=3) = (4,3) * (8-4 , 3-3) /( 8 ,3) = (4,3) * (4 , 0 ) /( 8 ,3) = 4 * 1 / [ 8!/(3!*5!) ] =

4*3!*5! /8! = 1/14

P(X=3) = 1/14

8 0

3 years ago

Consider a manufacturing process with a quality inspection station. In the past, 15% of parts are defective. As soon as one defe

Inga [223]

Answer:

0.614125

Step-by-step explanation:

Given that a manufacturing process with a quality inspection station has on an average 15% of parts are defective.

As soon as one defective part is found, the process is stopped.

We find that number of defectives would be binomial because each part randomly selected has a constant probability of 0.15 being defective

Probability that at least 11 total parts will be inspected before the process is stopped/8 parts have been inspected without finding a defective part

= $P(x\geq 11)/P(x=8)\\$

= Probability of 9th, 10th, 11th should not be defective

= $(1-0.15)^3\\= 0.614125$

6 0

3 years ago