Volume of square pyramid=lwh/3=225 in³.
l=w=Xin.
h=x/5in.
x³/15=225
x=15in.
The distance between the boats after 1 minute would be 130 ft.
Given that a lake is 200ft wide, and two boats start to move towards one another from opposite shores, and in one minute, the first boat goes 40 ft and the second one goes 30 ft, to determine what would be the distance between the boats after 1 minute the following calculation must be performed:
- Total width - boat distance 1 - boat distance 2 = Distance after 1 minute
- 200 - 40 - 30 = X
- 130 = X
Therefore, the distance between the boats after 1 minute would be 130 ft.
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Answer:
no
Step-by-step explanation:
Substitute x = 3 into the equation and if the result is 0 then it is a solution
y = 5(3) + 3 = 15 + 3 = 18 ≠ 0
Then (3, 0 ) is not a solution to the equation
Answer:
x = 10
Step-by-step explanation:
You can try the answers to see which works. (The first one does.)
Or, you can solve for the variable:
Divide by 75
... (1/5)^(x/5) = 3/75 = 1/25
Recognize that 25 = 5^2, so ...
... (1/5)^(x/5) = (1/5)^2
Equating exponents, you have
... x/5 = 2
... x = 10 . . . . . multiply by 5
_____
You can also start by taking logarithms:
... log(75) +(x/5)log(1/5) = log(3)
... (x/5)log(1/5) = log(3) -log(75) = log(3/75) = log(1/25) . . . . simplify the log
... x/5 = log(1/25)/log(1/5) = 2 . . . . . simplify (or evaluate) the log expression
... x = 10 . . . . . multiply by 5
_____
"Equating exponents" is essentially the same as taking logarithms.
Answer:
81
Step-by-step explanation:
162 divided by 2
