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hodyreva [135]
3 years ago
13

Pls help What is true about the following sequence: 2.7, 6.5, 10.3, 14.1, 17.9*

Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

<em>D.) It has a common difference of 3.8</em>

Step-by-step explanation:

When you subtract a_{2} -a_{1} you get a common difference, the same goes for the other values: when you subtract the previous term from the next, you get a common difference of positive 3.8

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What percent increase is 1/3 to 1/6
r-ruslan [8.4K]

Answer:

50% increase

Step-by-step explanation:

half of 6 is 3 thus 50%, and vise versa.

4 0
3 years ago
Who won the race between the two balls of string
motikmotik
The higher one I think
7 0
3 years ago
<img src="https://tex.z-dn.net/?f=2x%5E%7B2%7D%20%2B%203%20%3D%205" id="TexFormula1" title="2x^{2} + 3 = 5" alt="2x^{2} + 3 = 5"
sveta [45]

Answer:

x = 1

Step-by-step explanation:

  • 2x^2 + 3 = 5
  • 2x^2 = 5 - 3
  • 2x^2 = 2
  • x^2 = 2/2
  • x = \| 1
  • x = 1

6 0
3 years ago
A study that looked at beverage consumption used sample sizes that were much smaller than previous national surveys. One part of
Sholpan [36]

Answer:

Step-by-step explanation:

In statistics, about 68 percent of values come in one standard deviation of the mean by using a standard normal model.   Approximately 95% of the data were all within two standard deviations from the mean. Almost all of the data are in the range of three standard deviations of the mean (roughly 99.7%).

The 68-95-99.7 law, also known as the Empirical Rule, is based on this evidence. 68 percent of the data values of a naturally distributed data collection of small children with a mean of 8.2 and a standard deviation of 10.8 would be between -2.2 and 19.0.

Within a mean of 14.1 as well as a standard deviation of 8.2, 68 percent of the data values in a usually distributed data collection of older children would be between 5.9 and 22.3.

However, we cannot conclude that the data is naturally distributed since the real actual data vary from the usual normal curve computed above.

Hence, various measures like either goodness of fit or theory testing, would be used for this.

5 0
3 years ago
A bus is travelli ng with the velo ci ty of 60 km/hr . Pressin g the bra kes sud denly, it is reta rde d to 0.05 m/s2 . How fa r
solong [7]

Step-by-step explanation:

Initial velocity(u) = 60 km/hr = 50/3 m/s

final velocity(v)= 0 (stops at rest)

acceleration(a) = -0.05 m/s²

display (s)=?

v²-u²=2as

0²- (50/3)= 2(-0.05)s

2500/9= 0.1s

s= 25000/9 m

5 0
2 years ago
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