Volume generated by the areas R2 + R3 around the line OC
= (1/3) pi 1^2 * 3 = pi sq units
Volume generated by area R2 around OC is found as follows
the equation of the curve can be written as x = y^4 / 81
Integral between limits y = 0 and 3 of the curve is
pi INT x^2 dy = INT pi y^8 / 81^2 dx
= pi [3^9 / 9*81^2]
= pi/3
So the volume generated by R3 about OC = pi - pi/3 = 2pi/3
Answer:
2(x + 1) = 10
2x + 2 = 10
2x +2 -2 = 10 - 2
2x = 10(Step 3)
2x/2 = 8/2
x = 4
Step-by-step explanation:
Given the equation:
2(x + 1) = 10
Open the bracket by multiplying 2 by (x + 1) - Distributive property
2x + 2 = 10;
Subtract 2 from both sides.
2x + 2 - 2 = 10 - 2( Subtraction property of equality)
2x = 8(Step 3 justified).
Divide both sides by 2
2x/2 = 8/2 - Division property of equality.
Therefore,
x = 4. (Solved)
Answer:
C if im correct
Step-by-step explanation:
I have a similar problem
The answer is -2x^2-16x+8
Answer:
$5,850
Step-by-step explanation:
4.5% = 0.045
0.045 x 130,000 = 5850
