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ANTONII [103]
3 years ago
6

Which of the following is productivity strategy for collaboration?

Computers and Technology
1 answer:
mixer [17]3 years ago
8 0

Which of the following is a productivity strategy for collaboration?

  • A. Saving focused work for a time of day when you feel most creative.
  • B. Employing the 80/20 rule to prioritize tasks.
  • C. Posting files to a web-based shared site.
  • D. Using white noise to block distractions in the office.

<u>Answer:</u>

Posting files to a web-based shared site is a productivity strategy for collaboration.

  • C. Posting files to a web-based shared site.

<u>Explanation:</u>

Collaborative software or groupware is application programming intended to help individuals taking a shot at a typical errand to achieve their objectives. This permits individual to impart thoughts and their abilities to different individuals with the goal that the assignment can be done both proficiently and adequately.

Joint effort stages ordinarily incorporate an email customer, Web conferencing, internet based life sharing, video capacities, report sharing abilities, texting and that's just the beginning. Endeavor joint effort stages are intended to be introduced on-premises or conveyed by means of the Web as cloud-based administrations.

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After a group sets a project schedule, members should be prepared to
Roman55 [17]

After a group sets a project schedule, members should be prepared to complete a study-time survey to prove they can do the work.

<h3>What is a group project?</h3>

A group project is a project in which more than one person work together. Group projects are given to improve the work, as various minds can bring out various implements for the project.

Thus, the correct option is D. complete a study-time survey to prove they can do the work.

Learn more about group project

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3 0
2 years ago
The process of bringing data or a file from one program to another is called
Digiron [165]
The answer is importing
8 0
2 years ago
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A small company with 100 computers has hired you to install a local area network. All of the users perform functions like email,
charle [14.2K]

Answer:

Answer to the following question is as follows;

Explanation:

Windows 7 for 100 users and Windows 8.1 for 25 users are the best options since they both enable networking and active directory, and Windows 8.1 also offers Windows server capabilities.

Winxp would therefore work for $100, but it is unsupported and has no updates.

If you wish to go with open source, you can choose Ubuntu 16 or 18 or Linux.

8 0
3 years ago
Take the average of some numbers. Show all the numbers that are below average. You can assume that there will not be more than 2
olchik [2.2K]

Here is code in java.

import java.util.*; // import package

class Main //  creating class

{

public static void main (String[] args) // main method

{

Scanner br=new Scanner(System.in); // scanner class for input

       int []a=new int[20]; // declaring array

       int count=0,x,j; // creating variable

       int sum =0;

       System.out.println("Enter a weight (0 to stop):");

       x=br.nextInt(); // taking input

while(x!=0) // iterating over the loop

       {

           a[count] = x;

           count++;

           System.out.println("Enter a weight (0 to stop):");

           x=br.nextInt();

}

       for( j=0;j<count;j++) // iterating over the loop

       {

       sum+=a[j];

       }

       double avg = sum/(double)count;

       System.out.println("The total is: "+sum);

       System.out.println("The average is: "+avg);

       System.out.println("Here are all the numbers less than the average: ");

     for( j=0;j<count;j++) //  // iterating over the loop

       {

           if(a[j]<avg)

           System.out.print(a[j]+" ");

       }

}

}

Explanation:

First create an object of "Scanner" class to read input from the user.

Create an array of size 20, which store the number given by user.Ask user

to give input and keep the count of number in the variable "count". If user

give input 0 then it will stop taking input.And then calculate sum of all the

input.It will calculate average by dividing the sum with count and print it.

It will compare the all elements of array with average value, if the element

is less than average, it will print that element.

Output:

Enter a weight (0 to stop):

1

Enter a weight (0 to stop):

2

Enter a weight (0 to stop):

3

Enter a weight (0 to stop):

4

Enter a weight (0 to stop):

5

Enter a weight (0 to stop):

6

Enter a weight (0 to stop):

7

Enter a weight (0 to stop):

8

Enter a weight (0 to stop):

9

Enter a weight (0 to stop):

10

Enter a weight (0 to stop):

0

The total is: 55

The average is: 5.5

Here are all the numbers less than the average:

1 2 3 4 5

6 0
3 years ago
Describe how serial data access finds data
jeyben [28]

Answer:

Serial data access will go through all the data by order until the target data is reached

Explanation:

This is opposite of direct data access which immediately finds the desired

data

4 0
3 years ago
Read 2 more answers
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