Answer:
55
Explanation:
Given the codes as below:
- for (int a = 0; a < 10; a++)
- {
- for (int b = 10; b > a; b--)
- {
- System.out.print("#");
- }
- }
There are two layer loops in the code. The outer loop (Line 1) will run for 10 iterations by traversing through a = 0 to a=9. However, the inner loop (Line 3) will run for 10 + 9 + 8 + 7 +...+ 1 = 55 iterations.
Since the print statement is within the inner loop (Line 5) and therefore the number of printed "#" symbols is dependent on the number of iterations of the inner loop. There will be 55 "#" symbols printed.
The answer on this scenario would then be c. drop out. This effect can be done if one wants to break a color into one's percentage of the full strength. Hope this is the answer and would be of big help.
import random
num_rolls = 0
while True:
r1 = random.randint(1, 6)
r2 = random.randint(1, 6)
print("Rolled: " + str(r1) + "," + str(r2))
num_rolls += 1
if r1 == r2 == 1:
break
print("It took you "+str(num_rolls)+" rolls")
I added the working code. You don't appear to be adding to num_rolls at all. I wrote my code in python 3.8. I hope this helps.
Answer:
Tell her about cyber bullies
Tell her about hackers
stalkers
identity theft
spam
Sorry if wrong
Explanation:
Answer:
d. ICMP Echo Reply (type 0)
Explanation:
ICMP or internet control message protocol is an Internet layer protocol in the TCP/IP suite. It works together with routing devices like the router to send messages based on results sensed in the network.
The RFC 1122 has stated that the ICMP server and end user application be configured or installed in user devices, for receiving and sending ICMP echo request packets and reply. The process is called pinging.
For an attacker to implement ping of ping, he needs to confirm if the target user in live by sending an ICMP echo request packet type 8, to receive an ICMP echo reply type0.
