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3 years ago

6

Mark wants to maintain an average of 70 on his math tests to remain eligible for sports. So far, he earned scores of 68, 75, 74,

82, and 88. What is the lowest score he can earn on the next test to have an average of at least a 70?

1 answer:

Alex17521 [72]3 years ago

6 0

Answer:

Step-by-step explanation:

(68+75+74+82+88+x)/6=70

(387+x)/6=70

x= 33

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On a coordinate plane, a curved line, labeled f of x, with a minimum value of (negative 1.9, negative 5.7) and a maximum value o

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D- F(x) > 0 over the intervals ( –2.5, –0.75) and (0.75, ∞).

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ad-work [718]

Answer:

Point R is at (-40,30), a distance of 60 units from point Q

Step-by-step explanation:

<u>Explanation </u>

<u>we will use below conditions</u>

<u>Type of transformation</u> <u> change to co-ordinate point</u>

vertical translation up 'd' units (x, y) changes to (x, y +d)
vertical translation down 'd' units (x, y) changes to (x, y-d)
horizontal translation left 'c' units (x, y) changes to (x- c, y)

4. horizontal translation right 'c' units (x, y) changes to (x+ c , y)

now Given data is P( 20,-30) and in the graph Q(-40,-30)

Step1:-

<u>Now we have to find 'R' point</u>

Given data the point "R' is vertically above point Q so the point "Q' is moves vertically up with '60' units

now we will use the condition (1)

Q(-40,-30) is <u>vertical translation up '60' units </u>now changes the co-ordinate point is (-40 , -30+60)

<u>The correct translation and The point R( -40 , 30)</u>

<u>Step2:-</u>

Again in the given data "R" is at the same distance from point Q as point P is from point Q.

<u>so given P point is (20 , -30)</u>

now we translation 'P' also

<u>vertically translation up at a distance '60' units</u> and changes the new co-ordinate (20 , -30+60) that is (20,30) [ use above condition is (1)]

and again<u> horizontal translation left '60</u>' now changes (20 - 60 ,30)[ use condition (3)]

There fore the new co-ordinate is R( -40 , 30)

<u>Final answer:-</u>

Point R is at (−40, 30), a distance of 60 units from point Q

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3 years ago

A door 2m*1m is fixed on a wall.The wall is 8.5 long and 2m high.Find the cost of whitewashing the wall ₹40 per square meter.

Savatey [412]

Answer:

$600\ rupees$

Step-by-step explanation:

$We\ are\ given:\\Dimensions\ of\ the\ door=2m *1m\\Dimensions\ of\ the\ wall=8.5m*2m\\Cost\ of\ whitewashing\ of\ 1m^2=40\ rupees\\Hence,\\First\ lets\ consider\ the\ wall:\\Area\ of\ a\ rectangle= Length*Width\\Here,\\Length\ of\ the\ wall=8.5\ m\\Width\ of\ the\ wall=2\ m[As\ here\ width\ and\ height\ are\ the\ same\ thing]\\Hence,\\Area\ of\ the\ wall=8.5*2=17\ m^2$

$Now,\\Lets\ consider\ the\ door:\\As\ we\ know\ that,\\Area\ of\ a\ rectangle=Length*Width\\Here,\\Length\ of\ the\ door=2m\\Width\ of\ the\ door=1\ m\\Hence,\\Area\ of\ the\ door=2*1=2m^2\\\\Now,\\The\ area\ to\ be\ whitewashed=Area\ of\ the\ wall-Area\of\ the\ door\\Hence,\\The\ area\ to\ be\ whitewashed=17-2=15\ m^2\\\\As\ we\ know\ that,\\Cost\ of\ whitewashing\ 1\ m^2\ of\ the\ wall= 40\ rupees\\Hence,\\$

$Cost\ of\ whitewashing\ the\ whole\ wall=Area\ of\ the\ wall\ to\ be\\ whitewashed*Rate\ of\ whitewashing\ per\ m^2\\Hence,\\Cost\ of\ whitewashing\ the\ whole\ wall=15*40=600\ rupees$

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3 years ago

True or False: As the value of cos(x) approaches 1 and the value of sin(x) approaches 0, the value of tan(x) approaches infinity

nevsk [136]

Answer: False

Step-by-step explanation:

We can write tan(x) = sin(x)/cos(x)

if cos(x) tends to 1, and sin (x) tends to 0 (this happens aronund the point x = 0)

then we have:

Tan(x) = 0/1 = 0

Then the statement is false, as cos(x) approaches 1 and sin(x) approaches 0, tan(x) also approaches 0.

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4 years ago