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3 years ago

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Mark wants to maintain an average of 70 on his math tests to remain eligible for sports. So far, he earned scores of 68, 75, 74,

82, and 88. What is the lowest score he can earn on the next test to have an average of at least a 70?

1 answer:

Alex17521 [72]3 years ago

6 0

Answer:

Step-by-step explanation:

(68+75+74+82+88+x)/6=70

(387+x)/6=70

x= 33

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Graph the line y = -2x - 2

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Answer:

-2x-2

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The function has no undefined points nor domain

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Step-by-step explanation:

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2 years ago

60 students study a language at a school.

mixas84 [53]

The number of girls is 24.
The number of boys that study French is 24.
The numbber of boys that study German is 12.
The number of girls that study French is 16
The number of girls that study German is 8.

<h3>How to fill the frequency tree?</h3>

The number of girls = total number of students - total number of boys

60 - 36 = 24

The number of boys that study French = 2/3 x 36 = 24

The numbber of boys that study German = 36 - 24 = 12

The number of girls that study French = 40 - 24 = 16

The number of girls that study German = 24 - 16 = 8

Please find attached the frequency tree. To learn more about addition, please check: brainly.com/question/349488

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3 0

2 years ago

NO LINKS OR FILES!

Archy [21]

(a) If the particle's position (measured with some unit) at time <em>t</em> is given by <em>s(t)</em>, where

$s(t) = \dfrac{5t}{t^2+11}\,\mathrm{units}$

then the velocity at time <em>t</em>, <em>v(t)</em>, is given by the derivative of <em>s(t)</em>,

$v(t) = \dfrac{\mathrm ds}{\mathrm dt} = \dfrac{5(t^2+11)-5t(2t)}{(t^2+11)^2} = \boxed{\dfrac{-5t^2+55}{(t^2+11)^2}\,\dfrac{\rm units}{\rm s}}$

(b) The velocity after 3 seconds is

$v(3) = \dfrac{-5\cdot3^2+55}{(3^2+11)^2} = \dfrac{1}{40}\dfrac{\rm units}{\rm s} = \boxed{0.025\dfrac{\rm units}{\rm s}}$

(c) The particle is at rest when its velocity is zero:

$\dfrac{-5t^2+55}{(t^2+11)^2} = 0 \implies -5t^2+55 = 0 \implies t^2 = 11 \implies t=\pm\sqrt{11}\,\mathrm s \imples t \approx \boxed{3.317\,\mathrm s}$

(d) The particle is moving in the positive direction when its position is increasing, or equivalently when its velocity is positive:

$\dfrac{-5t^2+55}{(t^2+11)^2} > 0 \implies -5t^2+55>0 \implies -5t^2>-55 \implies t^2 < 11 \implies |t|$

In interval notation, this happens for <em>t</em> in the interval (0, √11) or approximately (0, 3.317) s.

(e) The total distance traveled is given by the definite integral,

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt$

By definition of absolute value, we have

$|v(t)| = \begin{cases}v(t) & \text{if }v(t)\ge0 \\ -v(t) & \text{if }v(t)$

In part (d), we've shown that <em>v(t)</em> > 0 when -√11 < <em>t</em> < √11, so we split up the integral at <em>t</em> = √11 as

$\displaystyle \int_0^8 |v(t)|\,\mathrm dt = \int_0^{\sqrt{11}}v(t)\,\mathrm dt - \int_{\sqrt{11}}^8 v(t)\,\mathrm dt$

and by the fundamental theorem of calculus, since we know <em>v(t)</em> is the derivative of <em>s(t)</em>, this reduces to

$s(\sqrt{11})-s(0) - s(8) + s(\sqrt{11)) = 2s(\sqrt{11})-s(0)-s(8) = \dfrac5{\sqrt{11}}-0 - \dfrac8{15} \approx 0.974\,\mathrm{units}$

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2 years ago

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Sergio039 [100]

The answer is c (1,R)

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3 years ago

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mash [69]

Answer:

the area of the actual living room floor is 24 square feet.

Step-by-step explanation:

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2 years ago

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