Let's approach this problem by slowly eliminating choices.
First consider the keyword
"at most" and
"no more than". This means that the inequality should be less than or equal to the constant value stated. This will automatically eliminate two choices with the greater than symbol favoring the variables - choices A and D.
Next we associate the right constants to the right coefficients of variables. The two kinds of weight the truck transports are 30 and 65 lbs, and we know that this should not exceed 3,800 lbs. This is therefore our first inequality. The other inequality is for the volume. The combinations of the two volumes 4 and 9 cubic feet should not exceed 400 cubic feet when transported.
If you try to construct the inequality and miss it among the choices, don't worry! Let's try doing some simplifications first and see if it matches either B or C.
After simplification you can get

from dividing the equation by 5 and

for leaving it as it is.
Looking carefully, we can see that this is equivalent to option B.
ANSWER: B.
Answer:
220 I'm pretty sure because 6×5 is 30 times 2 is 60. Then do 6×10 equals 60. Then do 5 times 10 times 2 to get 100. Then you add it all up to get 220
Answer:
Both flights approach each other at a speed of 624.70 Knots. The FAA minimum separation is not violated as both airplanes are 7.26 Nautical miles away from each other at the time when one of the flights( flight AA) passes through Frada Heights.
Step-by-step explanation:
To solve this kind of problem, the knowledge of concept of relative velocity is needed as the first question requested how fast the flights were approaching each other. To find the minimum distance between both flights, the closest point of approach between both flights should be taken into consideration which was Frada heights. Flight AA passes through Frada Heights in a shorter time of 0.079 hours. This is the time at which both flights approach each other the closest and so the minimum distance (separation) between them. This was calculated to be 7.26NM which is greater than the FAA's minimum this requirement for flight was not violated.
Detailed calculation steps can be found in the attachment below.
There are 1.505535375e+24 atoms in 2.50 moles of iron.
513 flowers because if you divided 2,050 by 4 you get 512.5, but if you round you get 513