Answer:
61 3/5
Step-by-step explanation:
we realize that 8 4/5 can be written as [8 + (4/5)]
hence 7 x 8 4/5
= 7 x [8 + (4/5)]
= 7 [8 + (4/5)] (use the distributive property, see attached for reference)
= 7(8) + 7(4/5)
= 56 + 28/5 (convert 28/5 into mixed fraction)
= 56 + 5 3/5
= 61 3/5 (answer)
So let's break this question down.
You need a bit of both, right? Well we need to calculate how many multiple choices we can do whilst having true/false questions, and not going over or under on points.
So, let's pick a random number, 5. So let's do 8x5, that equals 40.
ohmygoditsrightiwasseriouslyjustguessing
Ok so now we have our number, 5 multiple choice questions.
The true/false questions should be easy, just do 3x20 and you get 60.
ANSWER: 5
Answer:
C
Step-by-step explanation:
To make it easy let's start by organizing our information :
- AC=12 AND BD=8
- ABCD is a rhombus
- K and L are the midpoints of sides AD and CD
- we notice that the rhombus ABCD is divided into four right triangles
What do you think of when you hear a right triangle ?
- The pythagorian theorem !
AC and BD are khown so let's focus on them .
If we concentrated we can notice that AB and BD are cossing each other in the midpoints . why ?
Simply because they are the diagonals of a rhombus .
ow let's apply the pythagorian theorem :
- (AC/2)² + (BD/2)² = BC²
- 6²+4²=52
- BC²= 52⇒
=BC
Now we khow that : AB=BC=CD=AD=
This isn't enough . Let's try to figure out a way to calculate the length of KL wich is the base of the triangle
- KL is parallel to AC
- k is the midpoint of AD and L of DC
I smell something . yes! Thales theorem
- KL/AC=DL/DC=DK/AD WE4LL TAKE OLY ONE
- KL/12=/2*
- KL/12=1/2⇒ KL=6
Now we have the length of the base kl
Now the big boss the height :
- notice that you khow the length of KL
- BD crosses kl from its midpoint and DL = /2
What I want to do is to apply the pythgorian thaorem to khow the lenght of that small part that is not a part of the height of the triangle . I will call it D
- DL²=(KL/2)²+D²
- 52/4= 9+ D²
- D² = 52/4-9 +4 SO D=2
now the height of the trigle is H= BD-D= 8-2=6
NOw the area of the triangle is :
- A=(KL*H)/2 ⇒ A= (6*6)/2=18
THE ANSWER IS 18 SQ.UN
Full question :
A man buys a certain number of oranges at 20 for Rs. 60 and an equal number at 30 for Rs. 60. He mixes them and sells them at 25 for Rs. 60. What is the gain or loss percent?
Answer:
4% loss(percentage loss on cost price)
Step-by-step explanation:
we will be employing algebra in solving this problem :
20 oranges at 60 Rs=60Rs/20 per orange=3Rs per orange
Say x oranges bought at 3Rs per orange=3Rsx
Equal number of oranges at 30 oranges for 60 Rs=60Rs/30 per orange=2Rs per orange
Say x oranges bought at 3Rs per orange=2Rsx
Total Cost Price = 3Rsx + 2Rsx = 5Rsx
He then sells all oranges at 25 for 60 Rs
Therefore price per orange=60/25=12/5Rs
since he sold x+x oranges(from the above calculations)
Total selling price=total oranges *12/5Rs=2x oranges*12/5Rs=24x/5Rs
Profit or loss=24x/5-5x=-x/5
therefore we have a loss =-x/5
Percentage of loss(on cost price)
=x/5÷5x∗100=
=1/25∗100=4%
Answer:
0.5 pints
Step-by-step explanation:
