Answer:
z (min) = 360 x₁ = x₃ = 0 x₂ = 3
Step-by-step explanation:
Protein Carbohydrates Iron calories
Food 1 (x₁) 10 1 4 80
Food 2 (x₂) 15 2 8 120
Food 3 (x₃) 20 1 11 100
Requirements 40 6 12
From the table we get
Objective Function z :
z = 80*x₁ + 120*x₂ + 100*x₃ to minimize
Subjet to:
Constraint 1. at least 40 U of protein
10*x₁ + 15*x₂ + 20*x₃ ≥ 40
Constraint 2. at least 6 U of carbohydrates
1*x₁ + 2*x₂ + 1*x₃ ≥ 6
Constraint 3. at least 12 U of Iron
4*x₁ + 8*x₂ + 11*x₃ ≥ 12
General constraints:
x₁ ≥ 0 x₂ ≥ 0 x₃ ≥ 0 all integers
With the help of an on-line solver after 6 iterations the optimal solution is:
z (min) = 360 x₁ = x₃ = 0 x₂ = 3
Answer:0.60$
Step-by-step explanation:
15=9$
1=0.60$
Answer:
71.4 in ^2
Step-by-step explanation:
area of the circles = πr^2
3.14(4x4) = 50.24 but you only have half so divide by 2
= 25.12
second circle
3.14(2x2)= 13.56 again you only have half so divide by 2
= 6.28
square
5x8 = 40
add them all up
25.12+6.28+40 = 71.4
Add together to get -3
Multiply together to get -10
Can you think of the two numbers?
Try 2 and -5:
2+-5 = -3
2*-5 = -10.
Therefore, (x+2)(x-5) is the answer :)
D its aswer
Step-by-step explanation:
